Java实现从url路径下载文件到指定路径

 

代码实现：

 1 　　/**
 2      * 不带参数的get请求，如果状态码为200，则返回body，如果不为200，则返回null
 3      * @param urlStr 被下载文件的url
 4      * @param path 下载文件的路径和文件名
 5      * @throws Exception
 6      */
 7     public static void downloadFile(String urlStr, String path) {
 8         try {
 9             CloseableHttpClient httpClient = HttpClients.createDefault();
10             // 声明 http get 请求
11             URL url = new URL(urlStr);
12             URI uri = new URI(url.getProtocol(), url.getHost(), url.getPath(), url.getQuery(), null);
13             HttpGet httpGet = new HttpGet(uri);
14             // 发起请求
15             CloseableHttpResponse response = httpClient.execute(httpGet);
16 
17             // 判断状态码是否为200
18             if (response.getStatusLine().getStatusCode() == 200) {
19                 // 返回响应体的内容
20                 InputStream inputStream = response.getEntity().getContent();
21                 int index;
22                 byte[] bytes = new byte[1024];
23                 FileOutputStream downloadFile = new FileOutputStream(path);
24                 while ((index = inputStream.read(bytes)) != -1) {
25                     downloadFile.write(bytes, 0, index);
26                     downloadFile.flush();
27                 }
28                 inputStream.close();
29                 downloadFile.close();
30 
31             } else if (response.getStatusLine().getStatusCode() == 500){
32 
33                 throw new Exception(I18nUtil.getValueByKey("interfacecallfailed"));
34             }
35         } catch (Exception e) {
36             e.printStackTrace();
37         }
38     }

 

posted @ 2021-11-17 17:06  空指针终结者  阅读(204)  评论(0)    收藏  举报