leetcode Reverse Integer python

class Solution(object):
    def reverse(self, x):
        """
        :type x: int
        :rtype: int
        """
        answer = 0
        
        sign = 1 if x > 0 else -1
        x = abs(x)
        while x > 0:
            answer = answer * 10 + x % 10
            x/=10
        if answer > 2147483647:
            answer = 0
        return sign*answer

 

posted @ 2015-11-09 23:20  hao.ma  阅读(99)  评论(0编辑  收藏  举报