# coding:utf-8
def find_longest_no_repeat_substr(one_str):
'''''
找出来一个字符串中最长不重复子串
'''
res_list = []
length = len(one_str)
for i in range(length):#分别以字符串的每个字符作为自串的第一个字符
tmp = one_str[i]#记录不重复自串的中间变量
for j in range(i + 1, length):
if one_str[j] not in tmp:
tmp += one_str[j]
else:
break
res_list.append(tmp) #保存所有的不重复子串
res_list.sort(lambda x, y: cmp(len(x), len(y)),reverse = True)#根据每个不重复子串长度降序排列
return res_list[0]
if __name__ == '__main__':
one_str_list = ['120135435', 'abdfkjkgdok', '123456780423349']
for one_str in one_str_list:
res = find_longest_no_repeat_substr(one_str)
print '{0}最长非重复子串为:{1}'.format(one_str, res)