js-鸡兔同笼方程

实用:

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>Document</title>
</head>
<body>
    <script>
    var a=prompt("输入头总数");
    var b=prompt("输入脚总数");
	//根据m+n=a;2m+4n=b; 则推出
    var m=(4*a-b)/2;
    var n=(b-2*a)/2;
    document.write("那么鸡有",m,"只","<br>");
    document.write("兔有",n,"只","<br>");
    //alert("那么鸡有",m,"只","<br>");
    </script>
</body>
</html>

循环:

// 鸡兔同笼
//1.
var result = null
for (var i = 0; i < 35; i++) {
    for (var j = 0; j < 35; j++) {
        if ((i * 2) + (j * 4) == 94 && i + j == 35) {
            result = '鸡' + i + '兔' + j;
            break
        }
    }
}
// 2.(最佳)
var result = null
for (var i = 0; i < 35; i++) {
    var j = 35 - i;
    if ((i * 2) + (j * 4) == 94) {
        result = '鸡' + i + '兔' + j;
        break
    }
}
//同2
var result = null,
    i = 0
while (i < 35) {
    var j = 35 - i;
    if ((i * 2) + (j * 4) == 94) {
        result = '鸡' + i + '兔' + j;
        break
    }
    i++
}
posted @ 2020-04-13 22:43  千年轮回  阅读(1899)  评论(0编辑  收藏  举报