set集合

# s2={'周杰伦','周润发','周星星'}
# ret = s2.remove('周星星')
# s2.clear()
# print(s2)
# 修改
# s2={'周杰伦','周润发','周星星'}
# s2.remove('周杰伦')
# s2.add('德玛')

# 查询
# s2={'周杰伦','周润发','周星星'}
# for i in s2:
#     print(i)

# s2={'周杰伦','周润发','周星星'}
# s2.update((1,2,3))
# print(s2)
# s2={'周杰伦','周润发','周星星'}
# s1={'刘能','赵四','周星星'}
# 交集
# 两个集合中共有的元素
# print(s1&s2)
# 并集
# print(s1|s2)
# # 子集
# print(s1<s2)
# l=[1,2,3,4,5,6]
# lst = [i*2 for i in l]
# lst =[i for i in l if i%2 == 0]


# lst = [i for i in range(31) if i%3==0]
# lst = [i*i for i in range(31) if i%3==0]
# print(lst)


# names=[
#     ['Tom','Billy','Jefferson','Andrew','Webley','Steven'],
#     ['Alice','Jill','Ana','Wendy','Jennifer','Sherry','Eva']
# ]
# lst = [j for i in names for j in i if j.count('e')>=2]
# print(lst)


# 字典推导式
# dic = {'a':10,'b':34}
# new = {key:dic[key] for key in dic}
# new1 = {dic[key]:key for key in dic}
# print(new1)

# l1 = ['Tom','Billy','Jefferson','Andrew','Webley','Steven']
# lst=[i.upper() for i in l1 if len(i)>3]
# print(lst)

# 2. 求M中3,6,9组成得列表 M=[[1,2,3],[4,5,6],[7,8,9]]
# M=[[1,2,3],[4,5,6],[7,8,9]]
# lst=[j for i in M for j in i if j==3 or j==6 or j==9]
# print(lst)


# # 三元运算符
# a=10
# b=5
# max_num=0
# max_num=a if a>b else b
# print(max_num)

# lambda  参数：返回值
# func2 = lambda a,b:a+b
# print(func2(3,4))

# func =lambda a,b:a if a>b else b
# func =lambda a:'奇' if a%2==1 else '偶'
# func = lambda a:a if a>0 else -a
# print(func(0))
# func=lambda:1+2+3
# print(func())
# l=[1,2,3,12,3,6,3,4,6]
# for i in range(len(l)-1):
#     for j in range(len(l)-i-1):
#         if l[j]>l[j+1]:
#             l[j],l[j+1]=l[j],l[j+1]
# print(l)