/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public int kthSmallest(TreeNode root, int k) {
//二叉搜索树,左子如果不是空,则必小于该节点
//右子不为空,则必大于该节点。同样每个分支也都满足这个条件
Stack<TreeNode> st=new Stack<TreeNode>();
if(root==null)
return 0;
int res=0;
int count=0;
TreeNode temp=root;
while(temp!=null||!st.isEmpty())
{
if(temp!=null)
{
st.push(temp);
temp=temp.left;
}
else if(!st.isEmpty())
{
temp=st.pop();
count++;
if(count==k)
{
res=temp.val;
break;
}
if(temp.right!=null)
temp=temp.right;
else
temp=null;
}
}
return res;
}
}