python 按照自然数排序遍历文件 python os.listdir sort by natural sorting

 

 

import os
import re
def sorted_aphanumeric(data):
    convert = lambda text: int(text) if text.isdigit() else text.lower()
    alphanum_key = lambda key: [ convert(c) for c in re.split('([0-9]+)', key) ] 
    return sorted(data, key=alphanum_key)

file = sorted_aphanumeric(os.listdir("./2"))
for f in file:
    print(f) 

 

参考

https://stackoverflow.com/questions/4813061/non-alphanumeric-list-order-from-os-listdir

Python for whatever reason does not come with a built-in way to have natural sorting (meaning 1, 2, 10 instead of 1, 10, 2), so you have to write it yourself:

import re
def sorted_aphanumeric(data):
    convert = lambda text: int(text) if text.isdigit() else text.lower()
    alphanum_key = lambda key: [ convert(c) for c in re.split('([0-9]+)', key) ] 
    return sorted(data, key=alphanum_key)

You can now use this function to sort a list:

dirlist = sorted_aphanumeric(os.listdir(...))

posted on 2018-09-06 11:03  Maddock  阅读(689)  评论(0编辑  收藏  举报

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