用了一个“假方法“
#include<iostream>using namespace std;int main(){ long long n,y,r,s; cin>>s; r=s/(60*60*24); y=r/30; n=y/12; n=n+1970; y=y%12+1; r=r%30+1; cout<<n<<' '<<y<<' '<<r<<endl; return 0;}