Sum Root to Leaf Numbers——LeetCode
Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.
An example is the root-to-leaf path 1->2->3 which represents the number 123.
Find the total sum of all root-to-leaf numbers.
For example,
1 / \ 2 3
The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.
Return the sum = 12 + 13 = 25.
题目大意:给一个二叉树,每个节点都是0-9之间的数字,从根节点到叶结点表示一个数字,求所有的这些数字的和。
解题思路:这道题应该是考察DFS,可以直接DFS求解,或者中序遍历用queue也可以做,最近做题没什么状态,脑袋一团浆糊。
public int sumNumbers(TreeNode root) { return sum(root,0); } public int sum(TreeNode node,int sum){ if(node==null){ return 0; } if(node.left==null&&node.right==null){ sum=sum*10+node.val; return sum; } return sum(node.left,sum*10+node.val)+sum(node.right,sum*10+node.val); }

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