【BZOJ 2002】【Hnoi 2010】弹飞绵羊 分块||Link Cut Tree 两种方法

ShallWe,Yveh,hmy,DaD3zZ,四人吃冰糕从SLYZ超市出来后在马路上一字排开,,,吃完后发现冰糕棍上写着:“向狮子座表白:愿做你的小绵羊”,,,

好吧在这道题里我们要弹飞绵羊,有分块和lct两种方法。

分块:

#include<cmath>
#include<cstdio>
#define for1(i,a,n) for(int i=(a);i<=(n);i++)
#define for3(i,a,n) for(int i=(a);i>=(n);i--)
#define read(x) x=getint()
using namespace std;
inline int getint(){char c;int ret=0;for(c=getchar();c<'0'||c>'9';c=getchar());for(;c>='0'&&c<='9';c=getchar())ret=ret*10+c-'0';return ret;}
const int N=200003;
int n,o[N],t[N],w[N],step[N];
inline void work(int i){
	int j=i+t[i];
	if (j>n) w[i]=n+1,step[i]=1;
	if (o[i]==o[j]){
		w[i]=w[j];
		step[i]=step[j]+1;
	}else{
		w[i]=j;
		step[i]=1;
	}
}
int main(){
	read(n);
	for1(i,1,n) read(t[i]);
	int pn=floor(sqrt(n)),q,id,x,y;
	for1(i,1,n) o[i]=(i-1)/pn+1;
	for3(i,n,1) work(i);
	read(q);
	while (q--){
		read(id);
		if (id==1){
			read(x); x++; y=0;
			while (x<=n){
				y+=step[x];
				x=w[x];
			}
			printf("%d\n",y);
		}else{
			read(x); read(y); x++;
			t[x]=y;
			for3(i,x,1)
				if (o[x]==o[i]) work(i);
				else break;
		}
	}
	return 0;
}

LCT(为什么我的lct的常数辣么大T_T)

#include<cstdio>
#include<algorithm>
#define for1(i,a,n) for(int i=(a);i<=(n);i++)
#define read(x) x=getint()
using namespace std;
inline int getint(){char c;int ret=0;for(c=getchar();c<'0'||c>'9';c=getchar());for(;c>='0'&&c<='9';c=getchar())ret=ret*10+c-'0';return ret;}
const int N=200003;
struct node *null;
struct node{
	node();
	node *fa,*ch[2];
	int s;
	void count() {s=1+ch[0]->s+ch[1]->s;}
	bool pl() {return fa->ch[1]==this;}
	void setc(node *r,bool c) {ch[c]=r; r->fa=this;}
	bool check() {return fa==null||((fa->ch[0]!=this)&&(fa->ch[1]!=this));}
}*rt[N];
node::node(){s=1;fa=ch[0]=ch[1]=null;}
int n;
inline void Build(){null=new node;null->s=0;null->ch[0]=null->ch[1]=null->fa=null;}
inline void rotate(node *r){
	node *f=r->fa; bool c=r->pl();
	if (f->check()) r->fa=f->fa;
	else f->fa->setc(r,f->pl());
	f->setc(r->ch[c^1],c);
	r->setc(f,c^1);
	f->count(); r->count();
}
inline void splay(node *r){
	for(;!r->check();rotate(r))
		if (!r->fa->check()) rotate(r->fa->pl()==r->pl()?r->fa:r);
	r->count();
}
inline void access(node *r){
	for(node *c=null;r!=null;r=r->fa){
		splay(r);
		r->setc(c,1);
		r->count();
		c=r;
	}
}
inline void link(node *r,node *f){
	access(r); splay(r);
	r->ch[0]->fa=null; r->ch[0]=null; r->fa=f; r->count();
}
int main(){
	Build();
	int t,q,x,y;
	read(n);
	for1(i,1,n) rt[i]=new node;
	for1(i,1,n) {read(t); if (i+t<=n) rt[i]->fa=rt[i+t];}
	read(q);
	while (q--){
		read(x);
		if (x==1){
			read(y); y++;
			access(rt[y]); splay(rt[y]); printf("%d\n",rt[y]->s);
		}else{
			read(x); read(y); x++;
			if (x+y<=n) link(rt[x],rt[x+y]);
			else link(rt[x],null);
		}
	}
	return 0;
}

BeiYu的常数总是比我的要小,,本蒟蒻还得继续努力啊

posted @ 2016-03-09 21:10  abclzr  阅读(185)  评论(0编辑  收藏