实验6

task4

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#include <stdio.h>
#define N 10

typedef struct {
    char isbn[20];          // isbn号
    char name[80];          // 书名
    char author[80];        // 作者
    double sales_price;     // 售价
    int  sales_count;       // 销售册数
} Book;

void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);

int main() {
     Book x[N] = {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
                  {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30},
                  {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
                  {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90}, 
                  {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
                  {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
                  {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
                  {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
                  {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
                  {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};
    
    printf("图书销量排名(按销售册数): \n");
    sort(x, N);
    output(x, N);

    printf("\n图书销售总额: %.2f\n", sales_amount(x, N));
    
    return 0;
}
void output(Book x[], int n) {
    for (int i = 0; i < n; i++) {
        printf("%-20s %-25s %-20s %-10f %-10d\n", 
               x[i].isbn, x[i].name, x[i].author, x[i].sales_price, x[i].sales_count);
    }
}
void sort(Book x[],int n){
	for (int i=0;i<n-1;i++) {
        for (int j=0;j<n-i-1;j++) {
            if (x[j].sales_count < x[j + 1].sales_count) {
                Book t = x[j];
                x[j] = x[j+1];
                x[j+1] = t;
            }
        }
    }
} 
double sales_amount(Book x[],int n){
	double total=0.0;
	for(int i = 0;i < n; i++){
		total+= x[i].sales_price * x[i].sales_count;
	}
	return total;
}

![屏幕截图 2025-12-25 192813](https://img2024.cnblogs.com/blog/3708094/202512/3708094-20251225193116623-1345929635.pngk

task5

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![image](https://img2024.cnblogs.com/blog/3708094/202512/3708094-20251225195227693-8031587.png)

task6

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#include <stdio.h>
#include <string.h>
 
enum Role {admin, student, teacher};
 
typedef struct {
    char username[20];  // 用户名
    char password[20];  // 密码
    enum Role type;     // 账户类型
} Account;
 
 
// 函数声明
void output(Account x[], int n);    // 输出账户数组x中n个账户信息，其中，密码用*替代显示
 
int main() {
    Account x[] = {{"A1001", "123456", student},
                    {"A1002", "123abcdef", student},
                    {"A1009", "xyz12121", student},
                    {"X1009", "9213071x", admin},
                    {"C11553", "129dfg32k", teacher},
                    {"X3005", "921kfmg917", student}};
    int n;
    n = sizeof(x)/sizeof(Account);
    output(x, n);
 
    return 0;
}
void output(Account x[], int n) {
    char c = ' ';
    for (int i = 0; i <= n-1; i++) {
        printf(" %-20s", x[i].username);
        int a = strlen(x[i].password);
        for (int j = 0; j <= a-1; j++)
            printf("*");
        switch (x[i].type) {
        case admin:printf("\t\tadmin"); break;
        case student:printf("\t\tstudent"); break;
        case teacher:printf("\t\tteacher"); break;
        }
        printf("\n");
    }
}

task7

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#include <stdio.h>
#include <string.h>

typedef struct {
    char name[20];      // 姓名
    char phone[12];     // 手机号
    int  vip;           // 是否为紧急联系人，是取1；否则取0
} Contact; 
// 函数声明
void set_vip_contact(Contact x[], int n, char name[]);  // 设置紧急联系人
void output(Contact x[], int n);    // 输出x中联系人信息
void display(Contact x[], int n);   // 按联系人姓名字典序升序显示信息，紧急联系人最先显示


#define N 10
int main() {
    Contact list[N] = {{"刘一", "15510846604", 0},
                       {"陈二", "18038747351", 0},
                       {"张三", "18853253914", 0},
                       {"李四", "13230584477", 0},
                       {"王五", "15547571923", 0},
                       {"赵六", "18856659351", 0},
                       {"周七", "17705843215", 0},
                       {"孙八", "15552933732", 0},
                       {"吴九", "18077702405", 0},
                       {"郑十", "18820725036", 0}};
    int vip_cnt, i;
    char name[20];

    printf("显示原始通讯录信息: \n"); 
    output(list, N);

    printf("\n输入要设置的紧急联系人个数: ");
    scanf("%d", &vip_cnt);
    printf("输入%d个紧急联系人姓名:\n", vip_cnt);
    for(i = 0; i < vip_cnt; ++i) {
        scanf("%s", name);
        set_vip_contact(list, N, name);
    }

    printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
    display(list, N);
}
void set_vip_contact(Contact x[], int n, char name[]) {
    int i;
    int j;
    for(i=0;i<n;i++)
            {if(strcmp(x[i].name,name)==0){
                x[i].vip=1;}}
}
void display(Contact x[], int n) {
    int i, j, num=0;
    Contact t;

    for (i = 0; i < n; i++) {
        if (x[i].vip) {
            t = x[num];
            x[num] = x[i];
            x[i] = t;
            num++;
        }
    }

    for (i = 0; i < num-1; i++) {
        if (strcmp(x[i].name, x[i + 1].name) > 0) {
            t = x[i];
            x[i] = x[i + 1];
            x[i + 1] = t;
        }
    }

    for (i = num; i < n; i++) {
        for (j = i + 1; j < n; j++) {
            if (strcmp(x[i].name, x[j].name) > 0) {
                t = x[i];
                x[i] = x[j];
                x[j] = t;
            }
        }
    }

    output(x, n);
}
void output(Contact x[], int n) {
    int i;
    for (i = 0; i < n; ++i) {
        printf("%-10s%-15s", x[i].name, x[i].phone);
        if (x[i].vip)
            printf("%5s", "*");
        printf("\n");
    }
}