73课 1到100的奇数和偶数之和！ 

 1 #include <stdio.h>
 2 
 3 int main (void)
 4 {
 5     int i;
 6     int sum1 = 0;//奇数和
 7     int sum2 = 0;//偶数和
 8     
 9     for (i = 1; i<101; ++i)
10         
11         if (i%2 == 1)
12         {
13             sum1 += i;
14         }
15         else
16         {
17             sum2 += i;
18         }
19         printf("1到100的奇数之和 = %d\n",sum1);
20         printf("1到100的偶数之和 = %d\n",sum2);
21         
22         
23         
24         return 0;
25 }

 

#include <stdio.h>
int main (void){int i;int sum1 = 0;//奇数和int sum2 = 0;//偶数和for (i = 1; i<101; ++i)if (i%2 == 1){sum1 += i;}else{sum2 += i;}printf("1到100的奇数之和 = %d\n",sum1);printf("1到100的偶数之和 = %d\n",sum2);return 0;}

posted @ 2020-02-27 20:17  坚韧的菜鸟  阅读(1752)  评论(0)    收藏  举报