BZOJ2527Meteors

BZOJ2527
整体二分模板题
整体二分: 主要用于解决第K大问题

#include<cstdio>
#include<cctype>
#include<vector>
#include<cstring>
#include<string>
#include<climits>
using namespace std;
inline int read()
{
    int x = 0, flag = 1;
    char c;
    while(! isgraph(c = getchar()))
        if(c == '-')
            flag *= - 1;
    while(isgraph(c))
        x = x * 10 + c - '0', c = getchar();
    return x * flag;
}
void println()
{
    putchar('N'), putchar('I'), putchar('E'), putchar('\n');
}
void println(int x)
{
    if(x < 0)
        putchar('-'), x *= - 1;
    if(x == 0)
        putchar('0');
    int ans[1 << 4], top = 0;
    while(x)
        ans[top ++] = x % 10, x /= 10;
    for(; top; top --)
        putchar(ans[top - 1] + '0');
    putchar('\n');
}
const int MAXN = 1 << 19, MAXM = 1 << 19, MAXK = 1 << 19;
int n, m;
vector<int> a[MAXN];
int p[MAXN];
int ID[MAXN];
struct rain
{
    int L, R, delta;
    rain(){}
    rain(int L, int R, int delta): L(L), R(R), delta(delta){}
}opt[MAXK << 1];
const int oo = INT_MAX;
int T;
long long tree[MAXM];
void add(int u, int delta)
{
    for(int i = u; i <= m; i += (i & (- i)))
        tree[i] += (long long)delta;
}
void modify(int u, int flag)
{
    if(opt[u].L <= opt[u].R)
        add(opt[u].L, flag * opt[u].delta), add(opt[u].R + 1, - flag * opt[u].delta);
    else
    {
        add(1, flag * opt[u].delta), add(opt[u].R + 1, - flag * opt[u].delta);
        add(opt[u].L, flag * opt[u].delta);
    }
}
long long query(int u)
{
    long long ret = 0;
    for(int i = u; i; i -= (i & (- i)))
        ret += tree[i];
    return ret;
}
int tmp[MAXN], mark[MAXN], ans[MAXN];
void solve(int L, int R, int optL, int optR)
{
    if(optL >= optR)
    {
        for(int i = L; i <= R; i ++)
            ans[ID[i]] = optL;
        return;
    }
    int mid = (optL + optR) >> 1;
    while(T < mid)
        modify(++ T, 1);
    while(T > mid)
        modify(T --, - 1);
    int cnt = 0;
    for(int i = L; i <= R; i ++)
    {
        long long sum = 0, now = ID[i];
        for(int j = 0; j < a[now].size(); j ++)
        {
            sum += query(a[now][j]);
            if(sum >= p[now])
                break;
        }
        if(sum >= p[now])
            mark[now] = 1, cnt ++;
        else
            mark[now] = 0;
    }
    int L1 = L, L2 = L + cnt;
    for(int i = L; i <= R; i ++)
        if(mark[ID[i]])
             tmp[L1 ++] = ID[i];
        else
            tmp[L2 ++] = ID[i];
    for(int i = L; i <= R; i ++)
        ID[i] = tmp[i];
    solve(L, L1 - 1, optL, mid);
    solve(L1, L2 - 1, mid + 1, optR);
}
int main()
{
    #ifndef ONLINE_JUDGE
    freopen("BZOJ2527.in", "r", stdin);
    freopen("BZOJ2527.out", "w", stdout);
    #endif
    n = read(), m = read();
    for(int i = 1; i <= m; i ++)
        a[read()].push_back(i);
    for(int i = 1; i <= n; i ++)
        p[i] = read();
    int k = read();
    int cnt;
    for(int i = 1; i <= k; i ++)
    {
        int L = read(), R = read(), delta = read();
        opt[i] = rain(L, R, delta);
    }
    opt[k + 1] = rain(1, m, oo);
    int T = 0;
    memset(tree, 0, sizeof(tree));
    for(int i = 1; i <= n; i ++)
        ID[i] = i;
    solve(1, n, 1, k + 1);
    for(int i = 1; i <= n; i ++)
    {
        if(ans[i] > k)
            println();
        else
            println(ans[i]);
    }
}