SQL18 - 查找当前薪水排名第二多的员工编号emp_no

题目描述：

查找当前薪水(to_date='9999-01-01')排名第二多的员工编号emp_no、薪水salary、last_name以及first_name，你可以不使用order by完成吗

CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));

CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));

 

难易程度：

较难

 

解答：

使用了嵌套查询

select employees.emp_no,max(b.salary) as salary ,employees.last_name,employees.first_name
from employees left join 
(select * from salaries where salaries.emp_no <> (select a.emp_no
from (
select employees.emp_no,max(salaries.salary)
from employees left join salaries
on employees.emp_no = salaries.emp_no
where salaries.to_date='9999-01-01') a
)
) b
on employees.emp_no = b.emp_no
where b.to_date='9999-01-01'