离散实践1

#include<iostream>
using namespace std;
void main()
{
    int M,N,p,q,temp=1;
    char i,j;
    while(temp)            //控制程序是否要执行
    {
        cout<<"请输入你的选择temp:\n";
        cout<<"您输入0时:不再运行程序，直接退出程序。\n";
        cout<<"您输入1时:运行程序即输出二元关系矩阵。\n";
        cin>>temp;
        switch(temp)
        {
        case 0:  temp=0;break;
        case 1:
            cout<<"请输入两个数组的大小M,N："<<endl;
            cin>>M>>N;
            char *arr1=new char[M];
            char *arr2=new char[N];
            cout<<"请输入第一个集合arr1："<<endl;
            for(p=0;p<M;p++)
            {
                cin>>arr1[p];
            }
            cout<<"请输入第二个集合arr2："<<endl;
            for(p=0;p<N;p++)
            {
                cin>>arr2[p];
            }
            int** arr=new int*[M];//开辟一个动态二维数组，高M，宽N
            for(int K=0;K<M;K++)
            {
                arr[K]=new int[N];
            }
            for(q=0;q<M;q++)//数组初始化全为0
            {
                for( p=0;p<N;p++)
                {
                    arr[q][p]=0;
                }
            }
            cout<<"请输入二元关系以0结束"<<endl; //输入关系后，以输入0代表结束
            while(1)
            {    
                cin>>i;
                if(i=='0')
                    break;
                else
                {
                    cin>>j;
                    if(i>='a'&&i<='z'&&(j<'a'||j>'z'))
                    {
                        i=i-'0';//0的ascii码为48，a的ascii码是65，z的ascii码90
                        arr[(i-'0')-1][(j-'0')-1]=1;
                    }
                    if(j>='a'&&j<='z'&&(i<'a'||i>'z'))
                    {
                        j=j-'0';
                        arr[(i-'0')-1][(j-'0')-1]=1;
                    }
                    else if(i>='a'&&i<='z'&&j>='a'&&j<='z')
                    {
                        p=i-'0'-'0';
                        q=j-'0'-'0';
                        arr[p-1][q-1]=1;
                    }
                    else    
                        arr[(i-'0')-1][(j-'0')-1]=1;
                }
            }
            cout<<"该二元关系的矩阵为："<<endl;
            for(q=0;q<M;q++)
            {
                for(p=0;p<N;p++)
                {
                    cout<<arr[q][p]<<" ";
                }
                cout<<endl;
            }break;
        }
    }
}

 

#include<iostream>
using namespace std;

void output(int i,int j,int **a);
void choose(int **arr);


void main()
{
    int M,N;
    //int M=0,N=0;
    //int *array1=new int[M];
    //int *array2=new int[N];
    cout<<"Please input sizes of array1 and array2: "<<endl;
    cin>>M>>N;
    int** arr=new int*[M];//开辟一个动态二维数组，高M，宽N
    for(int k=0;k<N;k++)
        arr[M]=new int[N];
    for(int i=0;i<M;i++)
    {
        for(int j=0;j<N;j++)
            arr[i][j]=0;
    }
        choose(arr);
        output(M,N,arr);
}

void output(int M,int N,int **arr)
{
    for(int i=0;i<M;i++)
        for(int j=0;j<N;j++)
            cout<<arr[i][j]<<"-";
}

void choose(int **arr)
{
    int i,j;
    cout<<"Please input the two relations:"<<endl;
    cin>>i>>j;
    arr[i][j]=0;
}

 

#include<iostream>
using namespace std;

void output(int i,int j,int **a);
void choose(int **arr);


void main()
{
    int M,N,temp1,temp2;
    //int M=0,N=0;
    //int *array1=new int[M];
    //int *array2=new int[N];
end:cout<<"Please enter 1(continue) or 2(break) to choose:"<<endl;
    cin>>temp1;
    switch(temp1)
    {
    case 1:
        {
            cout<<"Please input sizes of height and width: "<<endl;
            cin>>M>>N;
            int** arr=new int*[M];//??????????,?M,?N
            for(int k=0;k<M;k++)
            arr[k]=new int[N];
            for(int i=0;i<M;i++)
            {
              for(int j=0;j<N;j++)
              arr[i][j]=0;
            }
            choose(arr);
            output(M,N,arr);
            cout<<"Please input number 1 to again or 2 to exit:"<<endl;
            cin>>temp2;
            switch(temp2)
            {
            case 1:
                goto end;
            case 2:
                exit(1);
            }
            system("pause");
        }
    case 2:
        break;
    }
}

void choose(int **arr)
{
    int i,j;
    cout<<"Please input the two relations:"<<endl;
    cin>>i>>j;
    i--;
    j--;
    arr[i][j]=1;
}

void output(int M,int N,int **arr)
{
    for(int i=0;i<M;i++)
    {
        for(int j=0;j<N;j++)
        {
            cout<<arr[i][j]<<"-";
        }
    cout<<endl;
    }
}