AFO

$vim$配置以及$linux$

vim的配置

  1 set nu "设置行标号                                     
  2 set tabstop=4 "这一条以及以下三条都把缩进设为4
  3 set shiftwidth=4
  4 set softtabstop=4
  5 set autochdir  "自动切换到当前目录
  6 set smartindent "以下两行都是智能缩进相关
  7 set autoindent
  8 set mouse=a "激活鼠标
  9 set cursorline "行高亮
 10 inoremap [ []<ESC>i
 11 inoremap ( ()<ESC>i
 12 inoremap " ""<ESC>i
 13 inoremap ' ''<ESC>i
 14 inoremap {<CR>  {<CR>}<ESC>O
 15 map <F9> <Esc> :w <CR> :!g++ -g % -o %< && ./%< <CR>
 16 map <F5> <Esc> :w <CR> :!g++ -g % -o %< && gdb %< <CR>
 17 

对拍

  1 #!/bin/bash
  2 while true; do
  3     ./sj > input
  4     ./zj < input > zjpt
  5     ./bl < input > blpt
  6     if diff zjpt blpt; then
  7         printf "AC\n"
  8     else
  9         printf "Wa\n"
 10         exit 0
 11     fi
 12 done                                                   

然后运行的时候就

chmod +x dp.sh

就行了

# include <bits/stdc++.h>

using namespace std;

int main()
{
	int n=0;
	while (1)
	{
		n++;
		printf("Test %d:\n",n);
		system("./data");
		system("./std");
		system("./my");
		if(system("diff std.out my.out"))
		{
			puts("WA");
			getchar();
		}else puts("AC");
	}
	return 0;
}

Windows下的vimrc

set nu
syntax on
colorscheme cake
highlight LineNr guifg=pink
highlight LineNr guibg=white
set tabstop=4
set shiftwidth=4
set softtabstop=4
set autochdir
set belloff=all
set nocompatible

set backspace=indent
set backspace=eol
set backspace=start
set backspace=2

set smartindent
set autoindent 
set guifont=Consolas:h15
set mouse=a
set cursorline
inoremap ( ()<Esc>i
inoremap [ []<Esc>i
inoremap ' ''<Esc>i
inoremap " ""<Esc>i
inoremap {<CR> {<CR>}<Esc>O

配色 ckae
效果

#include<cstring>
#include<cstdio>
#include<algorithm>
#include<iostream>
#define M 200000
using namespace std;

int n,m,k,a[M],mx,d[M],mn,tot,f[M],nx,B,C;

int main()
{
	scanf("%d",&n);
	if(n==1) {printf("NO"); return 0;}

	for(int i=1;i<=n;i++) 
	{
		scanf("%d",&a[i]), f[a[i]]++;
		if(a[i]>a[mx]) mx=i, tot=1;
		else if(a[i]==a[mx]) tot++, nx=i;
	}
	if(tot==1) {printf("NO"); return 0;}
	for(int i=a[mx];i>=1;i--)   
	{
		f[i]+=k;
		k=f[i]/10;
		f[i]%=10;
		if(f[i]) C=1;
	}
	if(k && C) {printf("NO"); return 0;}
	printf("YES\n");
	for(int i=a[mx];i>=1;i--) 
	{
		f[i-1]=(f[i-1]+f[i]/10);
		f[i]%=10;
		if(f[i])d[i]=(10-f[i])%10;
		if(f[i]) f[i-1]++;
	}
	d[a[mx]]++;
	if(d[a[mx]]==10) 
	{
		B=1;
		d[a[mx]]--;
	}
	for(int i=1;i<=n;i++)
	{
		if(mx!=i)
		{
			printf("0.");
			for(int j=1;j<a[i];j++) printf("0");
			if(!B || nx!=i)printf("1\n");
			else printf("%d",2);
			continue;
		}
		printf("0.");
		for(int j=1;j<=a[i];j++) printf("%d",d[j]);
		printf("\n");
	}
	
}
posted @ 2019-05-14 11:15  ZUTTER☮  阅读(356)  评论(0编辑  收藏  举报