2022HDU-Multi-University Training AC/DC

题目链接:https://acm.hdu.edu.cn/showproblem.php?pid=7192

LCT维护一下fail树形态,询问时把删除部分和没有被删除的部分交线附近暴力匹配一下。

#include<bits/stdc++.h>
#define N 400009
using namespace std;
typedef long long ll;
char s[N],s1[N];
int n,q;
int ch[N][26],siz[N],nxt[N];
int tr[N][2],si[N],val[N],f[N],fa[N];
int last,cnt,l[N],num,tg[N];
inline void pushup(int x){siz[x]=siz[tr[x][0]]+siz[tr[x][1]]+si[x]+val[x];}
inline bool ge(int x){return tr[f[x]][1]==x;}
inline bool isroot(int x){return tr[f[x]][0]!=x&&tr[f[x]][1]!=x;}
inline void rotate(int x){
    int y=f[x],o=ge(x);
    if(isroot(x))return;
    tr[y][o]=tr[x][o^1];f[tr[y][o]]=y;
    if(!isroot(y))tr[f[y]][ge(y)]=x;f[x]=f[y];
    f[y]=x;tr[x][o^1]=y;pushup(y);pushup(x);
}
inline void splay(int x){
    while(!isroot(x)){
        int y=f[x];
        if(isroot(y))rotate(x);
        else rotate(ge(x)==ge(y)?y:x),rotate(x);
    }
}
inline void access(int x){
    for(int y=0;x;y=x,x=f[x]){
        splay(x);
        si[x]+=siz[tr[x][1]];si[x]-=siz[y];tr[x][1]=y;
        pushup(x);
    }
}
inline void link(int x,int y){
    access(x);splay(x);access(y);splay(y);
    f[x]=y;si[y]+=siz[x];pushup(y);
}
inline void cut(int x,int y){
    access(x);splay(x);
    f[tr[x][0]]=0;tr[x][0]=0;
    pushup(x);
}
inline void del(int x){
    access(x);splay(x);
    val[x]=0;
    pushup(x);
}
inline void ins(int x){
    int p=last,np=++cnt;last=np;l[np]=l[p]+1;
    siz[np]=val[np]=1;
    for(;p&&!ch[p][x];p=fa[p])ch[p][x]=np;
    if(!p)fa[np]=1,link(np,1); 
    else{
        int q=ch[p][x];
        if(l[p]+1==l[q])fa[np]=q,link(np,q);
        else{
            int nq=++cnt;l[nq]=l[p]+1;
            memcpy(ch[nq],ch[q],sizeof(ch[q]));
            int y=fa[q];cut(q,y);link(nq,y);
            fa[nq]=fa[q];fa[q]=fa[np]=nq;
            link(q,nq);link(np,nq);
            for(;ch[p][x]==q;p=fa[p])ch[p][x]=nq;
        }
    }
}
int main(){
    ios::sync_with_stdio(false);
    int T;
    cin>>T;
    int x; 
    while(T--){
        cin>>(s+1)>>q;
        n=strlen(s+1);
        last=cnt=1;
        for(int i=1;i<=n;++i){
            ins(s[i]-'a');
            tg[i]=last;
        }
        int opt;
        int lst=0;
        while(q--){
            cin>>opt;
            if(opt==1){
                cin>>s1;
                s1[0]=((s1[0]-'a')^lst)%26+'a';
            //    cout<<s1<<"wowow"<<endl;
                ++n;
                s[n]=s1[0];
                ins(s1[0]-'a');
                tg[n]=last;
            }
            if(opt==2){
                num++;
                del(tg[num]);
            }
            if(opt==3){
                cin>>(s1+1);
                 int len=strlen(s1+1);
                 int now=1;
                 for(int i=1;i<=len;++i){
                     s1[i]=((s1[i]-'a')^lst)%26+'a';
                     now=ch[now][s1[i]-'a'];
                }
            //    cout<<s1+1<<" ?? "<<now<<endl;
                if(!now){
                    puts("0");
                    lst=0;
                }
                else{
                    access(now);splay(now);
                    int ans=siz[now]-siz[tr[now][0]];
                    int l=max(1,num-len+2);
                    int r=num+len-1;
                    int j=0;
                    for(int i=2;i<=len;++i){
                        if(j&&s1[j+1]!=s1[i])j=nxt[j];
                        if(s1[j+1]==s1[i])j++;
                        nxt[i]=j;
                    }
                    j=0;
                    for(int i=l;i<=r;++i){
                        if(j&&s1[j+1]!=s[i])j=nxt[j];
                        if(s1[j+1]==s[i])j++;
                        if(j==len)ans--,j=nxt[j];
                    }
                    printf("%d\n",lst=ans);
                }
            }
        }
        for(int i=0;i<=cnt;++i){
            memset(ch[i],0,sizeof(ch[i]));
            siz[i]=nxt[i]=tr[i][0]=tr[i][1]=si[i]=val[i]=f[i]=fa[i]=l[i]=0;
        }
        num=0;
    } 
    return 0;
}
posted @ 2022-08-10 15:49  comld  阅读(31)  评论(0编辑  收藏  举报