java8如何对list中的map元素根据一个key值进行排序

public static void main(String[] args) {
        Map<String, Object> map = new HashMap<String, Object>();
        map.put("name", "ZK");
        map.put("age", 13);

        Map<String, Object> map2 = new HashMap<String, Object>();
        map2.put("name", "ZA");
        map2.put("age", 15);

        Map<String, Object> map3 = new HashMap<String, Object>();
        map3.put("name", "CX");
        map3.put("age", 20);

        Map<String, Object> map4 = new HashMap<String, Object>();
        map4.put("name", "CX");
        map4.put("age", 18);

        List<Map<String, Object>> list = new ArrayList<Map<String,Object>>();
        list.add(map);
        list.add(map2);
        list.add(map3);
        list.add(map4);

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如上的代码排序方式为

 List<Map<String, Object>> collect =
  list.stream().sorted(Comparator.comparing(Test::comparingByName)
 .thenComparing(Comparator.comparing(Test::comparingByAge).reversed()))
                                                     .collect(Collectors.toList());

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其中Test为你的类名.comparingByName和comparingByAge则是两个方法

private static String comparingByName(Map<String, Object> map){
        return (String) map.get("name");
    }

    private static Integer comparingByAge(Map<String, Object> map){
        return (Integer) map.get("age");
    }

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借助这两个方法,取出map的参数进行对比