线段树成段更新的基础题,每次操作将x到y这个区间的值改为z,然后最后要求输出
的是1到n的区间和,根据线段树的性质,1到n的区间和其实就是sum[1]。
/*2012-08-08 16:07:20 Accepted 1698 1015MS 2280K 1407 B G++ Yu*/ #include<stdio.h> #define lson l, m, rt << 1 #define rson m + 1, r, rt << 1 | 1 const int MAXN = 100100; int sum[MAXN << 2], col[MAXN << 2]; int n, q; void PushUp(int rt) { sum[rt] = sum[rt << 1] + sum[rt << 1 | 1]; } void PushDown(int l, int r, int rt) { int m = l + r >> 1; if(col[rt]) { col[rt << 1] = col[rt << 1 | 1] = col[rt]; sum[rt << 1] = (m - l + 1) * col[rt]; sum[rt << 1 | 1] = (r - m) * col[rt]; col[rt] = 0; } } void build(int l, int r, int rt) { col[rt] = 0; sum[rt] = 1; if(l == r) return; int m = l + r >> 1; build(lson); build(rson); PushUp(rt); } void update(int L, int R, int c, int l, int r, int rt) { int m = l + r >> 1; if(L <= l && r <= R) { col[rt] = c; sum[rt] = (r - l + 1) * c; return; } PushDown(l, r, rt); if(L <= m) update(L, R, c, lson); if(R > m) update(L, R, c, rson); PushUp(rt); } int main() { int T, cas = 1, x, y, z; scanf("%d", &T); for(cas = 1; cas <= T; cas ++) { scanf("%d%d", &n, &q); build(1, n, 1); while(q --) { scanf("%d%d%d", &x, &y, &z); update(x, y, z, 1, n, 1); } printf("Case %d: The total value of the hook is %d.\n", cas, sum[1]); } return 0; }
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