package leetcode;
import java.util.ArrayList;
import java.util.List;
public class demo_46 {
public List<List<Integer>> permute(int[] nums) {
List<List<Integer>> list=new ArrayList<List<Integer>>();
//设置数组记录当前循环中该数字是否被访问
int[] visited=new int[nums.length];
for(int i=0;i<nums.length;i++) {
visited[i]=0;
}
backtrack(list,nums,new ArrayList<Integer>(),visited);
System.out.println(list);
return list;
}
public void backtrack(List<List<Integer>> list,int[] nums,List<Integer> alist,int[] visited) {
if(alist.size()==nums.length) {
list.add(new ArrayList<Integer>(alist));
}
else {
for(int j=0;j<nums.length;j++) {
//若当前数字已被访问则继续循环
if(visited[j]==1) {continue;}
alist.add(nums[j]);
visited[j]=1;
backtrack(list, nums,alist,visited);
alist.remove(alist.size()-1);
visited[j]=0;
}
}
}
public static void main(String[] args) {
// TODO Auto-generated method stub
demo_46 d46 = new demo_46();
int[] nums= {1,2,3};
d46.permute(nums);
}
}