MySql02 练习

#day-02

#1.选择工资不在5000到12000的员工的姓名和工资
SELECT last_name,salary
FROM employees
WHERE salary NOT BETWEEN 5000 AND 12000;

#2.选择在20号或50号部门工作的员工姓名和部门号
SELECT last_name,department_id
FROM employees
#where department_id in (20,50);
WHERE department_id = 20 OR department_id = 50;

#3.选择公司中没有管理者的员工姓名及job_id
SELECT last_name,job_id
FROM employees
WHERE manager_id <=> NULL;

#4.选择公司中有奖金的员工姓名，工资和奖金级别
SELECT last_name,salary,commission_pct
FROM employees
WHERE commission_pct IS NOT NULL;
#或
SELECT last_name,salary,commission_pct
FROM employees
WHERE NOT commission_pct IS NULL;

#5.选择员工姓名的第三个字母是a的员工姓名
SELECT last_name
FROM employees
WHERE last_name LIKE '__a%';

#6.选择姓名中有字母a和k的员工姓名
SELECT last_name
FROM employees
WHERE last_name LIKE '%a%' AND last_name LIKE '%k%';

#7.显示出表employees表中first_name以'e'结尾的员工信息
SELECT first_name,last_name
FROM employees
WHERE first_name LIKE '%e';
#或,使用正则表达式$ 以e结尾('e$')，^ 以e开头('^e')
SELECT first_name,last_name
FROM employees
WHERE first_name REGEXP 'e$';

#8.显示出表employees部门编号在80-100之间的姓名、工种
SELECT last_name,job_id,department_id
FROM employees
WHERE department_id BETWEEN 80 AND 100;

#9.显示出表employees的manager_id是100，101，110的员工姓名，工资，管理者id
SELECT last_name,salary,manager_id
FROM employees
WHERE department_id IN (100,101,110);