P4588 [TJOI2018]数学计算 (线段树)
用线段树维护操作序列,叶子结点存要乘的数,非叶子结点存区间乘积,每次输出tr[1] 就是答案。
1 #include<bits/stdc++.h> 2 #define ll long long 3 #define lson k << 1, l, mid 4 #define rson k << 1 | 1, mid + 1, r 5 #define ls k << 1 6 #define rs k << 1 | 1 7 #define mid ((l + r) >> 1) 8 using namespace std; 9 const int maxn = 100005; 10 ll tr[maxn << 2]; 11 int mod, t, q; 12 13 void update(int k) { 14 tr[k] = (tr[ls] * tr[rs]) % mod; 15 } 16 17 void build(int k, int l, int r) { 18 tr[k] = 1; 19 if (l == r) return ; 20 build(lson), build(rson); 21 } 22 23 void change(int k, int l, int r, int x, int val) { 24 if (l == r) { 25 tr[k] = (val == 0) ? 1 : val; 26 return ; 27 } 28 if (x <= mid) change(lson, x, val); 29 else change(rson, x, val); 30 update(k); 31 } 32 33 int main() { 34 scanf("%d", &t); 35 while (t--) { 36 scanf("%d %d", &q, &mod); 37 build(1, 1, q); 38 int opt, x; 39 for (int i = 1; i <= q; i++) { 40 scanf("%d %d", &opt, &x); 41 if (opt == 1) change(1, 1, q, i, x), printf("%lld\n", tr[1] % mod); 42 else change(1, 1, q, x, 0), printf("%lld\n", tr[1] % mod); 43 } 44 } 45 return 0; 46 }

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