「洛谷」P1957 口算练习题

 

链接：https://www.luogu.com.cn/problem/P1957

知识点：

1、字符串转整型

1 int zhuan(string a){
2     int ans1 = 0;
3     for(int i = a.size()-1;i>=0;i--){
4         int h = a[i]-'0';
5         ans1+=h*pow(10,a.size()-i-1);
6     }
7     return ans1;
8 }

2、整数位数

 1 int total(int k){
 2     int tot = 0;
 3     if(k<0||k==0){
 4         tot++;
 5     }//负数和0特判
 6     while(k){
 7         k/=10;
 8         tot++;
 9     }
10     return tot;
11 }

AC代码：

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 int total(int k){
 4     int tot = 0;
 5     if(k<0||k==0){
 6         tot++;
 7     }
 8     while(k){
 9         k/=10;
10         tot++;
11     }
12     return tot;
13 }
14 int zhuan(string a){
15     int ans1 = 0;
16     for(int i = a.size()-1;i>=0;i--){
17         int h = a[i]-'0';
18         ans1+=h*pow(10,a.size()-i-1);
19     }
20     return ans1;
21 }
22 string p;
23 int a,b,c;
24 int biao;
25 int main(){
26     int n;
27     cin>>n;
28     for(int i = 1;i<=n;i++){
29         cin>>p;
30         if(p=="a"){
31             cin>>a>>b;
32             c = a+b;
33             cout<<a<<'+'<<b<<'='<<c<<endl;
34             cout<<total(a)+total(b)+total(c)+2<<endl;
35             biao = 0;
36         }else if(p=="b"){
37             cin>>a>>b;
38             c = a-b;
39             cout<<a<<'-'<<b<<'='<<c<<endl;
40             cout<<total(a)+total(b)+total(c)+2<<endl;
41             biao = 1;
42         }else if(p=="c"){
43             cin>>a>>b;
44             c = a*b;
45             cout<<a<<'*'<<b<<'='<<c<<endl;
46             cout<<total(a)+total(b)+total(c)+2<<endl;
47             biao = 2;
48         }else{
49             a = bian(p);
50             cin>>b;
51             if(biao==0){
52                 c = a+b;
53                 cout<<a<<'+'<<b<<'='<<c<<endl;
54             cout<<total(a)+total(b)+total(c)+2<<endl;
55             biao = 0;
56             }else if(biao==1){
57                 c = a-b;
58             cout<<a<<'-'<<b<<'='<<c<<endl;
59             cout<<total(a)+total(b)+total(c)+2<<endl;
60             }else{
61                 c = a*b;
62             cout<<a<<'*'<<b<<'='<<c<<endl;
63             cout<<total(a)+total(b)+total(c)+2<<endl;
64             biao = 2;
65             }
66         }
67     }
68     return 0;
69 }
View Code

 

posted @ 2020-06-13 22:09  Xinaop  阅读(183)  评论(0)    收藏  举报