高精度

vector highlowdiv(vector v, long long b)
{
vector ans;
long long t = v[0];
for (int i = 1; i <= v.size(); i++)
{

ans.push_back(t / b);
t %= b;
t *= 10;
t += v[i];
}

while (ans.size() > 1 && ans.front() == 0)
ans.erase(ans.begin());

return ans;
}

posted @ 2021-10-21 22:16  多巴胺不耐受仿生人  阅读(54)  评论(0)    收藏  举报