高精度

vector highlowdiv(vector v, long long b)
{
vector ans;
long long t = v[0];
for (int i = 1; i <= v.size(); i++)
{

    ans.push_back(t / b);
    t %= b;
    t *= 10;
    t += v[i];
}

while (ans.size() > 1 && ans.front() == 0)
    ans.erase(ans.begin());

return ans;

}

posted @ 2021-10-21 22:16  多巴胺不耐受仿生人  阅读(39)  评论(0)    收藏  举报