05 2015 档案

摘要:Lowest Common Multiple Plus Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 40223 Accept... 阅读全文
posted @ 2015-05-29 20:07 Tovi 阅读(120) 评论(0) 推荐(0)
摘要:统计元音 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 45967 Accepted Submission(s): 18746... 阅读全文
posted @ 2015-05-29 19:21 Tovi 阅读(134) 评论(0) 推荐(0)
摘要:C语言合法标识符 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 45522 Accepted Submission(s): 1... 阅读全文
posted @ 2015-05-28 09:36 Tovi 阅读(141) 评论(0) 推荐(0)
摘要:发工资咯:) Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 38838 Accepted Submission(s): 215... 阅读全文
posted @ 2015-05-27 12:48 Tovi 阅读(178) 评论(0) 推荐(0)
摘要:绝对值排序 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 51632 Accepted Submission(s): 249... 阅读全文
posted @ 2015-05-26 20:51 Tovi 阅读(144) 评论(0) 推荐(0)
摘要:数列有序! Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 57448 Accepted Submission(s): 2475... 阅读全文
posted @ 2015-05-25 21:02 Tovi 阅读(226) 评论(0) 推荐(0)
摘要:母牛的故事 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 51707 Accepted Submission(s): 2592... 阅读全文
posted @ 2015-05-25 20:07 Tovi 阅读(131) 评论(0) 推荐(0)
摘要:字符串统计 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 51785 Accepted Submission(s): 2841... 阅读全文
posted @ 2015-05-25 18:32 Tovi 阅读(125) 评论(0) 推荐(0)
摘要:数据的交换输出 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 67624 Accepted Submission(s): 25... 阅读全文
posted @ 2015-05-25 17:09 Tovi 阅读(180) 评论(0) 推荐(0)
摘要:偶数求和 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 56836 Accepted Submission(s): 24787... 阅读全文
posted @ 2015-05-25 13:26 Tovi 阅读(144) 评论(0) 推荐(0)
摘要:青年歌手大奖赛_评委会打分 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 57800 Accepted Submission(... 阅读全文
posted @ 2015-05-24 12:01 Tovi 阅读(153) 评论(0) 推荐(0)
摘要:蟠桃记 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 41742 Accepted Submission(s): 31408 ... 阅读全文
posted @ 2015-05-24 10:28 Tovi 阅读(149) 评论(0) 推荐(0)
摘要:多项式求和 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 51327 Accepted Submission(s): 2988... 阅读全文
posted @ 2015-05-23 21:03 Tovi 阅读(130) 评论(0) 推荐(0)
摘要:水仙花数 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 120001 Accepted Submission(s): 3556... 阅读全文
posted @ 2015-05-23 18:00 Tovi 阅读(145) 评论(0) 推荐(0)
摘要:今天下午刚学完计数排序,故趁热打铁写下来吧。 #include using namespace std;int main(){ int a[10000], k, n, max; // 数组a为输入的数组 int c[10000], b[10000]; // 数组b存... 阅读全文
posted @ 2015-05-23 17:22 Tovi 阅读(189) 评论(0) 推荐(0)
摘要:求数列的和 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 54427 Accepted Submission(s): 3349... 阅读全文
posted @ 2015-05-23 15:58 Tovi 阅读(164) 评论(0) 推荐(0)
摘要:整除的尾数 Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 27646 Accepted Submission(s): 1171... 阅读全文
posted @ 2015-05-23 12:20 Tovi 阅读(232) 评论(0) 推荐(0)
摘要:数值统计 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 68704 Accepted Submission(s): 34511... 阅读全文
posted @ 2015-05-23 11:39 Tovi 阅读(130) 评论(0) 推荐(0)
摘要:平方和与立方和 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 111547 Accepted Submission(s): 3... 阅读全文
posted @ 2015-05-23 11:31 Tovi 阅读(144) 评论(0) 推荐(0)
摘要:除法也是利用数组模拟,不过这里不是直接按照除法的运算来,而是把除法转变为减法运算,从而求得结果。 以下代码是copy过来的 #include#includeint len1,len2;char s1[905];char s2[905];int re[905];void sub(){ int... 阅读全文
posted @ 2015-05-23 11:12 Tovi 阅读(240) 评论(0) 推荐(0)
摘要:利用递归算法 #include #includeusing namespace std;void trail(string[],int[],int,int);int main(){ int n,k=0; cout>n; string a[100]; int b[100]={0}; for (i... 阅读全文
posted @ 2015-05-21 12:24 Tovi 阅读(153) 评论(0) 推荐(0)
摘要:原理上也是采用数组模拟。 a[i] 12345 b[j] 23 用c[k]来保存每次的运算结果,k=i+j; c[i+j]=c[i+j]+a[i]*b[j]; 这里来模拟一次乘法过程: 123 * 12 ... 阅读全文
posted @ 2015-05-21 12:08 Tovi 阅读(146) 评论(0) 推荐(0)
摘要:大数的减法,同样的需要用数组保留输入的两个大数,然后将其转换成为整型数进行运算。代码如下 #include //此代码要求a-b,其中a大于b #includeint main(void){ char s1[505],s2[505]; while(scanf(... 阅读全文
posted @ 2015-05-19 21:26 Tovi 阅读(296) 评论(0) 推荐(0)
摘要:大树的加法,实则用数组去进行处理。将两个数的每位相加的结果先保存在整形数组中,然后逐位进行结果的转换。代码如下#include "stdio.h"#includeint max(int x,int y){ if (x>y) return x; else return y;}int ... 阅读全文
posted @ 2015-05-19 17:44 Tovi 阅读(142) 评论(0) 推荐(0)
摘要:对于递归算法,从开始到现在都还是让我头疼的一个算法,当然以后还有很多的算法让我头疼呢。但是慢慢地研究他,其实他也是好理解的,首先理解递归必须知道用递归需要满足的两个条件:一、需要有反复执行的过程,(也就是反复去执行自身了) 二、就要有跳出反复执行的出口,也就是跳出反复循环的条件了(专业... 阅读全文
posted @ 2015-05-16 09:59 Tovi 阅读(229) 评论(0) 推荐(0)
摘要:好吧,今天差点忘记更新我的博文了。我决定博文开始纳入算了。。。冒泡排序,这个算法是我接触算法的第一个算法,由于这个算法比较简单,所以刚入门算法的基本上一看一学就懂。但是还是要弄懂它的原理,这样在做题的时候才能做到熟练精通掌握。对于这个原理我是这么理解的,可以把它看成是一遍一遍的扫描... 阅读全文
posted @ 2015-05-15 18:35 Tovi 阅读(176) 评论(0) 推荐(0)