LightSpeed 的Left Join Bug解决方案

在使用LightSpeed对数据库进行Left Join或Right Join操作时,经常会报一些匪夷所思的异常。

明明表没有问题,表面上语句写的也没问题,可总是报错。看分析器里的SQL就知道了,是LightSpeed对Left Right Join的解析是有问题的。

注:LS对Left Join和 Right Join 最后都会解析成Group Join来处理

当然这种情况只是偶尔发生,是因为某些表及关系的创建方式问题(LS官网要求把项目发给他们来分析问题,嫌麻烦 就没有继续下去,具体原因就没有了解)

现在,可以用另外一种方式来绕过这个Bug(用FindBySQL或者存储过程也可以,但是我不想用SQL语句处理,因为表结构发生变化后,不能第一时间发现问题)

Query query2 = new Query
{
    EntityType = typeof(LQ_StudentApply),
    QueryExpression = Entity.Attribute<LQ_StudentApply>("LQ_SchoolId") == SchoolId,
    Order = Order.By("CreatedOn").Descending()
};
//通过OuterJoin来处理Left Join和Right Join
query2.Join = Join.Outer(typeof(LQ_StudentApply), typeof(LQ_Member), "Operator", "Id");
var rst1 = dbPlatform.Find(query2, query2.Mappings);
var saList = rst1.GetCollection<LQ_StudentApply>();
var oList = rst1.GetCollection<LQ_Member>();

//Inner Join
query2.Join = Join.Inner(typeof(LQ_StudentApply), typeof(LQ_Member), "LQ_MemberId", "Id");
var rst2 = dbPlatform.Find(query2, query2.Mappings);
var memList = rst2.GetCollection<LQ_Member>();

//拼合三个表的数据
var query = saList.Zip(memList, (sa, mem) => new
{
    SA = sa,
    Mem = mem
}).Zip(oList, (mix, o) => new
{
    MemberId = mix.Mem.Id,
    SId = mix.SA.Id,
    OperatorName = o != null ? o.RealName : ""
});

解析出来的SQL语句大体就是

SELECT *
FROM LQ_StudentApply SA
LEFT JOIN LQ_Member M ON SA.Operator = M.Id
INNER JOIN LQ_Member MEM ON SA.LQ_MemberId = MEM.Id
WHERE SA.LQ_SchoolId = 'SchoolId'
ORDER BY SA.CreatedOn DESC

 

posted @ 2015-07-30 10:30  TiestoRay  阅读(262)  评论(0编辑  收藏  举报