题链
Kruskal
#include <bits/stdc++.h>
using namespace std;
#define MS 200009
#define ls rt<<1
#define rs rt<<1|1
#define LL long long
#define MAXN 0x3f3f3f3f
int n,m;
struct node{
int u,v,val;
}p[MS];
int fa[MS];
int find(int x){
if(x == fa[x]) return x;
else return fa[x] = find(fa[x]);
}
void merge(int x,int y){
fa[find(y)] = find(x);
}
bool cmp(node t1,node t2){
return t1.val < t2.val;
}
int main() {
ios::sync_with_stdio(false);
cin >> n >> m;
for(int i=1;i<=n;i++) fa[i] = i;
for(int i=1;i<=m;i++){
cin >> p[i].u >> p[i].v >> p[i].val;
}
sort(p+1,p+m+1,cmp);
int ans = 0;
for(int i=1;i<=m;i++){
if(find(p[i].u) != find(p[i].v)){
merge(p[i].u,p[i].v);
ans += p[i].val;
}
}
int flag = 1;
for(int i=1;i<=n;i++){
if(find(i) != find(1)) flag = 0;
}
if(flag) cout << ans << "\n";
else cout << "orz\n";
return 0;
}
Prim
#include <bits/stdc++.h>
using namespace std;
#define MS 5009
#define ls rt<<1
#define rs rt<<1|1
#define LL long long
#define MAXN 0x3f3f3f3f
int n,m;
struct node{
int to,val;
};
vector<node > vc[MS];
struct nod{
int poi,val;
};
priority_queue<nod > Q;
int dis[MS];
int v[MS];
bool operator < (nod t1,nod t2){
return t1.val > t2.val;
}
int main() {
ios::sync_with_stdio(false);
cin >> n >> m;
for(int i=1;i<=m;i++){
int u,v,w;
cin >> u >> v >> w;
vc[u].push_back({v,w});
vc[v].push_back({u,w});
}
for(int i=1;i<=n;i++) dis[i] = MAXN;
dis[1] = 0;
Q.push({1,0});
int ans = 0;
while(!Q.empty()){
nod x = Q.top();
Q.pop();
if(v[x.poi]) continue;
v[x.poi] = 1;
ans += x.val; // 答案
for(auto &it:vc[x.poi]){
if(dis[it.to] > it.val){ // 相比 Dijkstra 少了源点到 x.poi 的距离
dis[it.to] = it.val;
if(!v[it.to]){
Q.push({it.to,dis[it.to]});
}
}
}
}
cout << ans << "\n";
return 0;
}