摘要:class Solution { public: int divide(int dividend, int divisor) { // 处理特殊情况 if (divisor == 1) return dividend; if (divisor == -1) { if (dividend == INT
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摘要:https://leetcode.cn/problems/ZL6zAn/ class Solution { public: void DFS(vector<vector<int>>& grid, int i, int j, int M, int N, int& sum) { if (grid[i][
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摘要:int removeElement(vector<int>& nums, int val) { int slow = 0; for (int fast = 0; fast < nums.size(); ++fast) { if (nums[fast] != val) { nums[slow++] =
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摘要:/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode() : val(0), next(nullptr) {} * ListNode(int x) :
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摘要:https://blog.csdn.net/weixin_39126199/article/details/118785065 https://leetcode.cn/problems/search-insert-position/ class Solution { public: int sear
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摘要:[LeetCode] 43. Multiply Strings 字符串相乘 #coding=utf8 def cal_str(str1, str2): num1_len = len(str1) num2_len = len(str2) #l1存较小的 l1 = '' l2 = '' if num1_
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