动态规划之最短路径（Floyd算法） 

 1 package main
 2 
 3 import (
 4     "fmt"
 5 )
 6 
 7 func floyd(m [][]int) {
 8     length := len(m[0])
 9     var min, i, j int
10     for k := 0; k < length; k++ {
11         for i = 0; i < length; i++ {
12             for j = 0; j < length; j++ {
13                 if m[i][k] > 0 && m[k][j] > 0 {
14                     min = m[i][k] + m[k][j]
15                     if min < m[i][j] || m[i][j] < 0{
16                         m[i][j] = min
17                     }
18                 }
19             }
20         }
21     }
22     for i = 0; i < length; i++ {
23         for j = 0; j < length; j++ {
24             fmt.Print(m[i][j], "\t")
25         }
26         fmt.Println("")
27     }
28 }
29 
30 func main() { 
31     m := [][]int{{0, 2, 9}, {8, 0, -1}, {1, -1, 0}}
32     floyd(m)
33 }

 

posted @ 2013-11-07 11:23  Sunlnx  阅读(330)  评论(0)    收藏  举报