numpy数组及处理:效率对比

def Sum(n):          

    a=list(range(n))
    b=list(range(0,50000*n,5))
    c=[]
    for i in range(len(a)):
        c.append(a[i]**2+b[i]**3)
    return c
print(Sum(20))
 
import numpy as py
 
def pySum(n):
    a=py.array(range(n))
    b=py.array(range(0,500000*n,n))
    c=[]
    for i in range(len(a)):
        c.append(a[i]**2+b[i]**3)
    return c
print(pySum(20))
 
 
import datetime
def new4():
    now1=datetime.datetime.now()
    Sum(30000)
    now2=datetime.datetime.now()
    pySum(30000)
    now3=datetime.datetime.now()
    print("sum执行时间(30W数据):" , now2-now1,"\npysum数组执行时间(30W数据):" , now3-now2)
new4()
 
 
 
 
执行结果:
posted @ 2018-10-02 20:12  SpaldingWen  阅读(185)  评论(0编辑  收藏  举报