Kendo-UI-Grid-template 模板列不能及时刷新问题 

 1  var ShowAlarmColor = new Jfunction(J.use.dataItem)
 2             {
 3                 J.debugger,
 4                 (J.var.colStyle="<div style='background: #eeeeee;margin:0px; padding:0px'> " + J.use.dataItem.CheckStandard + "</div>"),
 5                 new Jswitch(J.use.dataItem.ALARMLEVEL)
 6                 {
 7                        new Jcase(0){ (J.use.colStyle="<div style='background: #eeeeee;margin:0px; padding:0px'> " + J.use.dataItem.CheckStandard + "</div>"),J.@break},
 8                        new Jcase(1){ (J.use.colStyle="<div style='background: #00FF00;margin:0px; padding:0px'> " + J.use.dataItem.CheckStandard + "</div>"),J.@break},
 9                        new Jcase(2){ (J.use.colStyle="<div style='background: #FFFF00;margin:0px; padding:0px'> " + J.use.dataItem.CheckStandard + "</div>"),J.@break},
10                        new Jcase(3){ (J.use.colStyle="<div style='background: #FFAAFF;margin:0px; padding:0px'> " + J.use.dataItem.CheckStandard + "</div>"),J.@break},
11                        new Jcase(4){ (J.use.colStyle="<div style='background: #FF3333;margin:0px; padding:0px'> " + J.use.dataItem.CheckStandard + "</div>"),J.@break},
12                 },
13                 J.@return(J.use.colStyle),
14             };
修改数据源后调用refresh方法 
grid.GetJQuery().refresh(),

　　

posted @ 2016-10-28 17:19  wono  阅读(1899)  评论(0)    收藏  举报