实验1 C语言开发环境使用和数据类型,运算符,表达式

实验一:

 

1.

源代码:

 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 int main (){
 4     printf(" O \n");
 5     printf("<H>\n");
 6     printf("I I\n");
 7     printf(" O \n");
 8     printf("<H>\n");
 9     printf("I I\n");
10     system("pause");
11     return 0;
12 }
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 2.

源代码:

1 #include<stdio.h>
2 #include<stdlib.h>
3 int main (){
4     printf(" O     0\n");
5     printf("<H>   <H>\n");
6     printf("I I   I I\n");
7     system("pause");
8     return 0;
9 }
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 实验二:

源代码:

 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 
 4 int main(){
 5     double a,b,c;
 6     scanf("%lf%lf%lf",&a,&b,&c);
 7     if((a+b)>c&&(a+c)>b&&(b+c)>a)
 8         printf("能够成三角形");
 9     else
10         printf("不能构成三角形");
11     system("pause");
12     return 0;
13 }
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 实验三:

源代码:

 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 
 4 int main()
 5 {
 6     char ans1,ans2;
 7     printf("每次课前认真预习,课后及时复习了没?(输入y或Y表示有,输入n或N表示没有)");
 8     ans1=getchar();
 9     getchar();
10     printf("\n动手敲代码实践了没?(输入y或Y表示敲了,输入n或N表示木有敲)");
11     ans2=getchar();
12     if((ans1=='y'|| ans1 == 'Y')&&(ans2=='Y'||ans2=='y'))
13         printf("\n罗马不是一天建成的,继续保持哦:)\n");
14     else
15         printf("\n罗马不是一天毁灭的,我们来建设吧\n");
16     system("pause");
17     return 0;
18 }
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实验四:

源代码:

 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 
 4 int main()
 5 {
 6     double x, y, z;
 7     char c1, c2, c3;
 8     int a1, a2, a3;
 9 
10     scanf_s("%d%d%d", &a1, &a2, &a3);
11     printf("a1=%d,a2=%d,a3=%d\n",a1,a2,a3);
12 
13     scanf("%c%c%c", &c1, &c2, &c3);
14     printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3);
15 
16     scanf("%lf,%lf", &x, &y);
17     printf("x = %f, y = %lf\n", x, y);
18 
19     system("pause");
20     return 0;
21 
22 }
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 实验五:

源代码:

 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 
 4 int main()
 5 {
 6     int year;
 7     int second = 1;
 8     int i = 1;
 9     double a,b;
10     for (i = 1; i < 10; i++)
11     {
12         second *= 10;
13     }    
14     year = second / (60 * 60 * 24 * 365);
15     a = second - year * 60 * 60 * 24 * 365;
16     b = a / (60 * 60 * 24 * 365);
17     if (b >= 0.5)
18         year += 1;
19     printf("10亿秒约等于%d年\n", year);
20     system("pause");
21     return 0;
22 }
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 实验六:

源代码:

 1 #include<stdio.h>
 2 #include<math.h>
 3 #include<stdlib.h>
 4 
 5 int main()
 6 {
 7     double x, ans;
 8     while(scanf("%lf", &x)!=EOF)
 9     {
10         ans = pow(x, 365);
11         printf("%.2f的365次方是:%.2lf\n", x, ans);
12         printf("\n");
13     }
14     system("pause");
15     return 0;
16 }
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 实验七:

源代码:

 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 
 4 int main()
 5 {
 6     double c, f;
 7     while (scanf_s("%lf", &c) != EOF)
 8     {
 9         f = 9 * c / 5 + 32;
10         printf("摄氏度c=%.2f时,华氏度f=%.2f\n", c, f);
11 
12     }
13     system("pause");
14     return 0;
15 }
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 实验八:

源代码:

 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 #include<math.h>
 4 
 5 int main()
 6 {
 7     int a, b, c;
 8     double s, area;
 9     while (scanf_s("%d%d%d", &a, &b, &c) != EOF) 
10     {
11         s = (double)(a + b + c)/ 2;
12         area = sqrt(s*(s - a)*(s - b)*(s - c));
13         printf("a=%d,b=%d,c=%d\n", a, b, c);
14         printf("area=%f", area);
15     }
16     system("pause");
17     return 0;
18 }
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posted @ 2026-03-22 17:14  郑云翔  阅读(12)  评论(0)    收藏  举报