SQL

常看到问题,如何取出每组的前N条记录。方便大家参考于是便把常见的几种解法列出于下。
问题:有表 如下,要求取出各班前两名(允许并列第二)

Table1

+----+------+------+-----+

| id |SName |ClsNo |Score|

+----+------+------+-----+

| 1 |AAAA | C1 | 67 |

| 2 |BBBB | C1 | 55 |

| 3 |CCCC | C1 | 67 |

| 4 |DDDD | C1 | 65 |

| 5 |EEEE | C1 | 95 |

| 6 |FFFF | C2 | 57 |

| 7 |GGGG | C2 | 87 |

| 8 |HHHH | C2 | 74 |

| 9 |IIII | C2 | 52 |

| 10 |JJJJ | C2 | 81 |

| 11 |KKKK | C2 | 67 |

| 12 |LLLL | C2 | 66 |

| 13 |MMMM | C2 | 63 |

| 14 |NNNN | C3 | 99 |

| 15 |OOOO | C3 | 50 |

| 16 |PPPP | C3 | 59 |

| 17 |QQQQ | C3 | 66 |

| 18 |RRRR | C3 | 76 |

| 19 |SSSS | C3 | 50 |

| 20 |TTTT | C3 | 50 |

| 21 |UUUU | C3 | 64 |

| 22 |VVVV | C3 | 74 |

+----+------+------+-----+

结果如下 +----+------+------+-----+

| id |SName |ClsNo |Score|

+----+------+------+-----+

| 5 |EEEE | C1 | 95 |

| 1 |AAAA | C1 | 67 |

| 3 |CCCC | C1 | 67 |

| 7 |GGGG | C2 | 87 |

| 10 |JJJJ | C2 | 81 |

| 14 |NNNN | C3 | 99 |

| 18 |RRRR | C3 | 76 |

+----+------+------+-----+

方法一: selecta.id,a.SName,a.ClsNo,a.Score fromTable1 a leftjoinTable1 b ona.ClsNo=b.ClsNoanda.Score<b.Score groupbya.id,a.SName,a.ClsNo,a.Score havingcount(b.id)<2 orderbya.ClsNo,a.Scoredesc

方法二:

select* fromTable1 a where2>(selectcount(*) fromTable1whereClsNo=a.ClsNo andScore>a.Score) orderbya.ClsNo,a.Scoredesc

方法三: select* fromTable1 a whereid in(selectidfromTable1 whereClsNo=a.ClsNoorderbyScoredesc limit 2) orderbya.ClsNo,a.Scoredesc

方法....
这里列出了多种SQL语句的实现方法,有些是MySQL特有的(Limit, 其它数据库可根据实际更改,比如oracle的rownum,MS SQL SERVER 的 top,..),有时是SQL标准支持的。但效率上和应用的场合或许不同。具体应用时可根据实际表中的记录情况,索引情况进行选择。

特例 N=1 ,即取最大的/最小的一条记录。 +----+------+------+-----+ | id |SName |ClsNo |Score| +----+------+------+-----+ | 5 |EEEE | C1 | 95 | | 7 |GGGG | C2 | 87 | | 14 |NNNN | C3 | 99 | +----+------+------+-----+

select * from Table1 a where not exists (select 1 from Table1 where ClsNo=a.ClsNo and Score>a.Score);

select a.* from Table1 a inner join (select ClsNo, max(Score) as mScore from Table1 group by ClsNo) b on a.ClsNo=b.ClsNo and a.Score=b.Score

 

select * from (select * from Table1 order by Score desc) t group by ClsNo

posted on 2012-08-27 11:14  J.L_  阅读(331)  评论(0)    收藏  举报

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