摘要: A - Strictly Increasing? 答案为No\(\iff\)存在\(i\in[1,n)\),使得\(a_i\ge a_{i+1}\)。 点击查看代码 #include<bits/stdc++.h> #define N 110 using namespace std; int n,a[ 阅读全文
posted @ 2025-03-01 23:26 Sinktank 阅读(770) 评论(0) 推荐(2)
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