Shirlies
宁静专注认真的程序媛~

吐吐槽吧:本来思路完全对了,但是那个二分查找搞错了,我还以为一个就可以了,结果查找上界和下界分别要一个查找函数(WA时就看了一下别人的代码,发现别人都是用两个查找函数的,模仿别人写的查找函数),自己得好好揣摩揣摩。。。

还有就是最后的结果可能是负数。。。因为get_sum的值是小于9901的,而N的值可大于9901

代码如下:
 1 #include <cstdio>
 2 #include <cstring>
 3 #include <algorithm>
 4 
 5 const int mod = 9901;
 6 const int maxn = 100000 + 100;
 7 
 8 int a[maxn];
 9 int val[maxn];
10 int c[maxn];
11 int N,D,num;
12 
13 int binary_find1(int x,int l,int r)
14 {
15     int ans = r;
16     while(l <= r)
17     {
18         int mid = (l + r) / 2;
19         if(val[mid] <= x) l = mid + 1,ans = mid;
20         else r = mid - 1;
21     }
22 
23     return ans;
24 }
25 
26 int binary_find2(int x,int l,int r)
27 {
28     int ans = l;
29     while(l <= r)
30     {
31         int mid = (l + r) / 2;
32         if(val[mid] < x) l = mid + 1;
33         else r = mid - 1,ans = mid;
34     }
35     return ans;
36 }
37 int get_sum(int x)
38 {
39     int sum = 0;
40     while(x > 0)
41     {
42         sum += c[x];
43         sum = sum % mod;
44         x -= (x & (-x));
45     }
46 
47     return sum;
48 }
49 
50 void insert(int x,int v)
51 {
52     while(x < num)
53     {
54         c[x] += v;
55         c[x] = c[x] % mod;
56         x += (x & (-x));
57     }
58 }
59 
60 int main()
61 {
62     while(scanf("%d%d",&N,&D) == 2)
63     {
64         for(int i = 1;i <= N;i ++)
65         {
66             scanf("%d",&a[i]);
67             val[i] = a[i];
68         }
69         std::sort(val + 1,val + N + 1);
70         num = 2;
71         for(int i = 2;i <= N; i ++)
72         {
73             if(val[i] != val[i -1])
74                 val[num ++] = val[i];
75         }
76         memset(c,0,sizeof(c));
77         for(int i = 1;i <= N;i ++)
78         {
79             int k = binary_find1(a[i],1,num - 1);
80             int x = binary_find1(a[i]+ D,1,num -1);
81             int y = binary_find2(a[i] - D,1,num-1); 
82             int ans = 1;
83             ans += get_sum(x);
84             ans -= get_sum(y - 1);
85             ans %= mod;
86             insert(k,ans);
87         }
88 
89         printf("%d\n",((get_sum(num-1) - N)%mod +mod)%mod);
90     }
91 
92     return 0;
93 }

 

 

posted on 2012-04-30 16:55  Shirlies  阅读(305)  评论(0编辑  收藏  举报