2016 百度校招研发算法题 9.12

 

很简单，直接ac：

 1 #include "iostream"
 2 
 3 using namespace std;
 4 
 5 int n, t, tag = 1;
 6 int main()
 7 {
 8     cin >> n;
 9 
10     if (n % 2 == 1)
11         t = n;
12     else
13         t =n+ 1;
14 
15     for (int i = 0; i < t; i++)
16     {
17         cout << n;
18     }
19     cout << endl;
20 
21     for (int i = 0; i < n; i++)
22     {
23         for (int j = 1; j <= t; j++)
24         {
25             if (j == (t / 2 + 1))
26             {
27                 cout << tag++;
28                 continue;
29             }
30             cout << n;
31 
32         }
33         cout << endl;
34     }
35 }

 

 

2

思路：

dfs，找出联通的房子，再判断对角是否为空地

 

 1 #include "iostream"
 2 #include "vector"
 3 using namespace std;
 4 
 5 char s[101][101];
 6 int N, M;
 7 int di[4] = { 1, -1, 0, 0 };
 8 int dj[4] = { 0, 0, 1, -1 };
 9 vector<int> area;
10 
11 int dfs(int i, int j, int *mini, int *minj, int *maxi, int *maxj) {
12     if (i < *mini)
13         *mini = i;
14     if (i > *maxi)
15         *maxi = i;
16     if (j < *minj)
17         *minj = j;
18     if (j > *maxj)
19         *maxj = j;
20     s[i][j] = 'x';
21     int a = 1;
22     for (int d = 0; d < 4; ++d) {
23         int ni = i + di[d], nj = j + dj[d];
24         if (s[ni][nj] == '1')
25             a += dfs(ni, nj, mini, minj, maxi, maxj);
26     }
27     return a;
28 }
29 
30 bool isBeauty(int mini, int minj, int maxi, int maxj)
31 {
32     if (s[mini - 1][minj - 1] == '0'
33         &&s[mini - 1][maxj + 1] == '0'
34         &&s[maxi + 1][minj - 1] == '0'
35         &&s[maxi + 1][maxj + 1] == '0')
36         return true;
37     else
38         return false;
39 }
40 
41 int main() {
42     cin >> N >> M;
43     memset(s, '0', sizeof(s));
44     for (int i = 0; i < N; ++i)
45         cin >> s[i + 1] + 1;
46 
47     int n1 = 0, n2 = 0;
48     for (int i = 1; i <= N; ++i)
49         for (int j = 1; j <= M; ++j)
50             if (s[i][j] == '1') {
51                 n1++;
52                 int mini = i, maxi = i, minj = j, maxj = j;
53                 int s = dfs(i, j, &mini, &minj, &maxi, &maxj);
54                 area.push_back(s);
55                 if (isBeauty(mini, minj, maxi, maxj))
56                     n2++;
57             }
58     cout << n2 << endl;
59 
60     system("pause");
61     return 0;
62 }

 

posted @ 2016-09-14 19:08  SeeKHit  阅读(449)  评论(0)  编辑  收藏  举报