GTM 84 - Ch 2 - Application of Unique Factorization
It seems that we always use UF (distribution of factors) to consider the relation "|" , "<"(approximation of \(\pi(x), \theta(x)\)), represent the natural numbers(\(\sum1/p\) diverges, Mobius Inversion, Dirichlet Product).
1 Results
Notes: we consider UFD, "1" stands for units group.
1.1 In the Ring \(\mathbb{Z}\) there are infinitely many prime numbers.
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Euclide's method
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Double counting method
Notes: \(\mathbb{Z}_p\)(all the rational numbers \(a/b, \ p\not|\ b\)) is UFD, but there is only one prime, all primes are associate
\(\mathbb{Z}_p\): \(a/b, \ p \not | \ b,\ a,\ b\in \mathbb{Z}\)
1.2 Arithmetic Functions
A Mobius Inversion Theorem(\(I \circ\mu=\mathbb{I}\))
Let \(F(n)=\sum_{d|n}f(d)\), Then \(f(n)=\sum_{d|n}F(n/d)\mu(d)\)
It is easy understand to use Dirichlet Product!
Notes:
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We can give a more general form if we think it from combinatorics
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We can give another proof for "\(\phi(n)=n\prod(1-\frac{1}{p_i})\)" using Inversion
B Dirichlet Product
Let A={mutiplicative function}
(A, Dirichlet Product) form a group.
1.3 \(\sum1/p\) Diverges
A \(\sum\frac{1}{p}\) diverges
B \(\sum q^{-deg\ p(x)}\) diverges
proof:
\(p_i(x)\) denote the monic irreducible polynomial
It is easy to find \(\lambda(n)\) diverges, and
So it makes sense.
1.4 The Growth of \(\pi(x)\)
- Eulcide
- square-free counting
- Consider the factor
- Utilize the bounds of \(\theta(x)\) and the relation between \(\pi(x)\) and \(\theta(x)\); analysize the factors of \(\left( \begin{array}{c} 2n \\ n \end{array} \right)\)
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