[LeetCode]Search a 2D Matrix
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
- Integers in each row are sorted from left to right.
- The first integer of each row is greater than the last integer of the previous row.
For example,
Consider the following matrix:
[ [1, 3, 5, 7], [10, 11, 16, 20], [23, 30, 34, 50] ]
Given target = 3, return true.
class Solution {
public:
bool searchMatrix(vector<vector<int> > &matrix, int target) {
int row=matrix.size();
int col=matrix[0].size();
int i=0;
int j=col-1;
while(i<row&&j>=0)
{
int temp=matrix[i][j];
if(temp==target) return true;
else if(temp>target) j--;
else i++;
}
return false;
}
};

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