day16_04_作业

# 1、函数对象优化多分支if的代码练熟

# def login():
#     print('登录功能:')
#
# def transfer():
#     print('转账功能:')
#
# def check_balance():
#     print('查询余额:')
#
# def withdrow():
#     print('提现:')
#
#
# func_dic={
#     '0':['退出',None],
#     '1':['登录',login],
#     '2':['转账',transfer],
#     '3':['查询',check_balance],
#     '4':['提现',withdrow]
# }
#
# while True:
#     for k in func_dic:
#         print(k,func_dic[k][0])
#
#
#     choice = input('请输入命令编号:').strip()
#
#     if not choice.isdigit():
#         print('请输入数字!')
#         continue
#
#     if choice == '0':
#         print('退出成功!')
#         break
#
#     if choice in func_dic:
#         func_dic[choice][1]()
#
#     else:
#         print('输入的命令不存在!')

'''
 2、编写计数器功能，要求调用一次在原有的基础上加一
        温馨提示：
            I:需要用到的知识点：闭包函数+nonlocal
            II:核心功能如下：
                def counter():
                    x+=1
                    return x


        要求最终效果类似
            print(couter()) # 1
            print(couter()) # 2
            print(couter()) # 3
            print(couter()) # 4
            print(couter()) # 5
'''

def outer():
    x=0
    def counter():
        nonlocal x
        x += 1
        return x
    return counter

counter=outer()
print(counter())
print(counter())
print(counter())