摘要:
A - Tiny Arithmetic Sequence 水题,判断3个数是否能构成等差数列 void solve() { int a, b, c; cin >> a >> b >> c; if (a + b == 2 * c || a + c == 2 * b || b + c == 2 * a) 阅读全文
摘要:
A. 时间统计 scanf 读入即可快速分割数据 using ll = long long; void solve() { int D, h, m, s; ll T[2]; for (int i = 0; i < 2; ++i) { scanf("%dday%02d:%02d:%02d", &D, 阅读全文