CF1214B

CF1214B

解法：

暴力枚举，时间复杂度 $ O(n) $

CODE:

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
 
using namespace std;
 
#define LL long long
#define N 100010
 
int r,b,n,ans;
 
int main() {
    scanf("%d%d%d",&b,&r,&n);
    for(int i = 0 ; i <= n ; i++) {
        int j = n - i;
        if(i > b) continue;
        if(j > r) continue;
        ans++;
    }
    printf("%d \n",ans);
    //system("p
    return 0;
}