Mini program

1.Shopping cart

 1 # bug分开添加同一种商品到购物车的时候  会以两种商品打印
 2 # 未对用户输入的字符串进行判断
 3 goods_name = [
 4     {"Name": "MI 8", "Price": 3699},
 5     {"Name": "MI 6", "Price": 2699},
 6     {"Name": "MI mini", "Price": 169},
 7     {"Name": "MI watch", "Price": 179},
 8 ]
 9 print("Welcome to Rainm's shopping center!!\nWhat do you want to do:")
10 choice = input("1. Enter the shop\n2. I am just looking")
11 shopping_car = []
12 flag = True
13 total = 0
14 if choice == '2':
15     print("See you next time")
16 else:
17     print("Nice to meet you, here are good: ")
18     while flag:
19         for i, k in enumerate(goods_name):         #枚举??
20             print("No.{}    {}         {}".format(i + 1, k["Name"], k["Price"]))
21         goods_choice = int(input("Which goods you want to add it to your shopping car(Press -1 to exit): "))
22         if goods_choice == -1:
23             print("What do you want to do:")
24             next_choice = input("1. check shopping car\n2. I want to see the next store")
25             if next_choice == '1':
26                 print("Here are your shopping car: ")
27                 for k in shopping_car:
28                     print("Name: {}   Price: {}      Count:{}".format(k["Name"], k["Price"], k["Count"]))
29                     total += int(k["Price"] * goods_num)
30                 print("Total:{}$".format(total))
31             else:
32                 print("See you next time.")
33                 break
34             flag = False
35             print("What do you want to do: ")
36             next_choice1 = input("1. Balance my shopping car.\n2. Continue to shopping.\n3. Exit the store.")
37             if next_choice1 == '1':
38                 shopping_car.clear()
39                 print("Balance successfully!!It totally costs {}$\nHaving a nice day!".format(total))
40             elif next_choice1 == '2':
41                 flag = True
42 
43         else:
44             goods_num = int(input("And how much do you want to buy: "))
45             shopping_car.append({"Name": goods_name[goods_choice - 1]["Name"], "Price": goods_name[goods_choice - 1]["Price"], "Count": goods_num})

 

posted @ 2018-09-10 11:22  Rainm  阅读(784)  评论(0编辑  收藏  举报