寒假训练 - 随笔分类 - Radium_1209

摘要：Oil DepositsTime Limit: 1000MS Memory Limit: 10000KTotal Submissions:20263 Accepted: 10621DescriptionThe GeoSurvComp geologic survey c... 阅读全文

posted @ 2018-03-16 23:24 Radium_1209 阅读(189) 评论(0) 推荐(0)

摘要：Bound FoundTime Limit: 5000MS Memory Limit: 65536KTotal Submissions:5254 Accepted:1686 Special JudgeDescriptionSignals of most probabl... 阅读全文

posted @ 2018-03-10 11:10 Radium_1209 阅读(114) 评论(0) 推荐(0)

摘要：1088 - Points in Segments PDF (English)StatisticsForumTime Limit: 2 second(s)Memory Limit: 32 MBGiven n points (1 dimensional) and q... 阅读全文

posted @ 2018-02-26 14:10 Radium_1209 阅读(100) 评论(0) 推荐(0)

摘要：Train Problem ITime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 42596 Accept... 阅读全文

posted @ 2018-02-26 12:01 Radium_1209 阅读(130) 评论(0) 推荐(0)

摘要：1.DFS搜索图析2.BFS搜索图析3.保留16位int前八位以及后八位#include int main(){ int n,a,b; while(scanf("%d",&n)!=EOF) { a=n>>8&0xFF; //保留前八位 b=n&0xFF; //保... 阅读全文

posted @ 2018-02-26 11:19 Radium_1209 阅读(93) 评论(0) 推荐(0)

摘要：1.求最大公约数最小公倍数int gcd(int m,int n){ if (m==0) return n; else return gcd(n%m,m);}通常采用辗转相除法求最大公约数，此处使用了递归来实现。int gcd(int m,int n){ int... 阅读全文

posted @ 2018-02-06 23:30 Radium_1209 阅读(95) 评论(0) 推荐(0)

摘要：1.multiset/set的使用#include multiset s; //set s;区别：multiset元素可重复，set不可重复，其内容有序。set常见成员列表:begin()--返回指向第一个元素的迭代器clear()--清除所有元素count()--返... 阅读全文

posted @ 2018-02-03 22:22 Radium_1209 阅读(91) 评论(0) 推荐(0)

摘要：MANAGERTime Limit: 1000MS Memory Limit: 10000KTotal Submissions:3112 Accepted: 1106DescriptionOne of the programming paradigm in paral... 阅读全文

posted @ 2018-02-03 21:51 Radium_1209 阅读(138) 评论(0) 推荐(0)

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