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Problem 9: Special Pythagorean triplet

flag = 0
for a in range(1,1000):
    for b in range(a+1,1000):
        if a*a + b*b == (1000-a-b)**2:
            print(a,b)
            flag = 1
            break
    if flag == 1:
        break

print(a*b*(1000-a-b))

 

posted on 2018-04-27 11:12  中年小Q  阅读(106)  评论(0编辑  收藏  举报