//1.将每个区间按右端点从小到大排序
//2.从前往后依次枚举每个区间,如果当前区间中已经包含点,就直接跳过,否则,选择当前区间的右端点
//选右端点的话,可以尽可能的包含在多个区间里
#include <iostream>
#include <algorithm>
using namespace std;
const int N = 100010;
int n;
struct Range {
int l, r;
bool operator< (const Range &W)const {
return r < W.r;
}
} range[N];
int main() {
scanf("%d", &n);
for (int i = 0; i < n; i ++ ) scanf("%d%d", &range[i].l, &range[i].r);
sort(range, range + n);
int res = 0, ed = -2e9;
for (int i = 0; i < n; i ++ )
if (range[i].l > ed) {
res ++ ;
ed = range[i].r;
}
printf("%d\n", res);
return 0;
}