对列表中的字典按照键值进行排序

alist = [
{"a":5,"b":2},
{"a":2,"b":8},
{"a":8,"b":2}
]

# for i in alist:
#     print(i['a'])
# #
# list = [i['a'] for i in alist]
# print(sorted(list))
# for k in alist

# li = [{"day": 2}, {"day": 1}, {"day": 3}]
newlist = sorted(alist, key=lambda k: k['a'])
print(newlist)

li = [{a:1,b:2,c:3,d:4},{e:5,f:6,g:7,h:8}]

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2
li = [{"day":2},{"day":1},{"day":3}]
newlist = sorted(li, key=lambda k: k['day'])
或者：

1
2
3
from operator import itemgetter
li = [{"day":2},{"day":1},{"day":3}]
newlist = sorted(li, key=itemgetter('day'))
运行结果都是：

1
[{'day': 1}, {'day': 2}, {'day': 3}]

https://zhidao.baidu.com/question/1239629746232186939.html