实验4

实验任务1.1

#include<stdio.h>
#define N 4
void test1(){
 int a[N] = {1,9,8,4};
 int i;
 printf("sizeof(a)=%d\n",sizeof(a));
 for(i = 0;i<N;++i)
  printf("%p:%d\n",&a[i],a[i]);
 printf("a = %p\n",a);
}

void test2(){
 char b[N] = {1,9,8,4};
 int i;
 printf("sizeof(b)=%d\n",sizeof(b));
 for(i = 0;i<N;++i)
  printf("%p:%d\n",&b[i],b[i]);
 printf("b = %p\n",b);
}
int main()
{
 printf("测试1: int类型一维数组\n");
 test1();
 
 printf("\n测试2: char类型一维数组\n");
 test2();
 return 0;
 } 

实验任务1.2

#include <stdio.h>
#define N 2
#define M 4

void test1() {
    int a[N][M] = {{1, 9, 8, 4}, {2, 0, 4, 9}};
    int i, j;
    printf("sizeof(a) = %d\n", sizeof(a));
    for (i = 0; i < N; ++i)
        for (j = 0; j < M; ++j)
            printf("%p: %d\n", &a[i][j], a[i][j]);
    printf("\n");
    printf("a = %p\n", a);
    printf("a[0] = %p\n", a[0]);
    printf("a[1] = %p\n", a[1]);
    printf("\n");
}

void test2() {
    char b[N][M] = {{'1', '9', '8', '4'}, {'2', '0', '4', '9'}};
    int i, j;
    printf("sizeof(b) = %d\n", sizeof(b));
    for (i = 0; i < N; ++i)
        for (j = 0; j < M; ++j)
            printf("%p: %c\n", &b[i][j], b[i][j]);
    printf("\n");
    printf("b = %p\n", b);
    printf("b[0] = %p\n", b[0]);
    printf("b[1] = %p\n", b[1]);
}

int main() {
    printf("测试1: int型两维数组");
    test1();
    printf("\n测试2: char型两维数组");
    test2();
    return 0;
}

实验任务2

#include <stdio.h>
#include <string.h>
#define N 80
void swap_str(char s1[N], char s2[N]);
void test1();
void test2();
int main() {
printf("测试1: 用两个一维char数组，实现两个字符串交换\n");
test1();
printf("\n测试2: 用二维char数组，实现两个字符串交换\n");
test2();
return 0;
}

void test1() {
char views1[N] = "hey, C, I hate u.";
char views2[N] = "hey, C, I love u.";
printf("交换前: \n");
puts(views1);
puts(views2);
swap_str(views1, views2);
printf("交换后: \n");
puts(views1);
puts(views2);
} 

void test2() {
char views[2][N] = {"hey, C, I hate u.",
"hey, C, I love u."};
printf("交换前: \n");
puts(views[0]);
puts(views[1]);

swap_str(views[0], views[1]);
printf("交换后: \n");
puts(views[0]);
puts(views[1]);
} 

void swap_str(char s1[N], char s2[N]) {
char tmp[N];
strcpy(tmp, s1);
strcpy(s1, s2);
strcpy(s2, tmp);
}

实验任务3.1

#include<stdio.h>

#define N 80

int count(char x[]);
int main()
{
    char words[N+1];
    int n;
    
    while(gets(words)!=NULL)
    {
        n = count(words);
        printf("单词数: %d\n\n", n);
    }
    return 0;
 } 
 
 int count(char x[])
 {
     int i;
     int word_flag = 0;
     int number = 0;
     
     for(i = 0;x[i]!='\0';i++){
         if(x[i]==' ')
             word_flag=0;
         else if(word_flag==0){
             word_flag = 1;
             number++;
         }
     } 
     return number;
 }

试验任务3.2

#include<stdio.h>
#define N 1000

int main(){
    char line[N];
    int word_len;
    int max_len;
    int end;
    int i;
    
    while(gets(line)!=NULL){
        word_len = 0;
        max_len = 0;
        end = 0;
        
        i = 0;
        while(1){
            while(line[i]==' '){
                word_len = 0;
                i++;
            }
            while(line[i]!='\0'&&line[i]!=' '){
                word_len++;
                i++;
            }
            if(max_len < word_len){
                max_len = word_len;
                end = i;
            }
            if(line[i]=='\0')
                break;
        }
        printf("最长单词: ");
        for(i = end - max_len;i<end;++i)
            printf("%c",line[i]);
        printf("\n\n");
    }
    
    return 0;
}

实验任务4

#include<stdio.h>
#define N 100
void dec_to_n(int x,int n);

int main(){
    int x;
    printf("输入一个十进制整数: ");
    while(scanf("%d",&x)!=EOF){
        dec_to_n(x,2);
        dec_to_n(x,8);
        dec_to_n(x,16);
        
        printf("\n输入一个十进制整数: ");
    }
    return 0;
} 

void dec_to_n(int x,int n)
{
    int a,b,c=0;
    switch(n)
    {
        case 16:printf("%x\n",x);break;
        case 8:printf("%o\n",x);break;        
        case 2:while(x!=0)
        {
            a=x%2;
            c=c*10+a;
            x=x/2;
                }    
        printf("%d\n",c);    
    }
    
}

 实验任务5

#include <stdio.h>
#define N 5

void input(int x[], int n);
void output(int x[], int n);
double average(int x[], int n);
void bubble_sort(int x[], int n);

int main() {
    int scores[N];
    double ave;
    
    printf("¼Èë%d¸ö·ÖÊý:\n", N);
    input(scores, N);
    
    printf("\nÊä³ö¿Î³Ì·ÖÊý: \n");
    output(scores, N);
    
    printf("\n¿Î³Ì·ÖÊý´¦Àí: ¼ÆËã¾ù·Ö¡¢ÅÅÐò...\n");
    ave = average(scores, N);
    bubble_sort(scores, N);
    
    printf("\nÊä³ö¿Î³Ì¾ù·Ö: %.2f\n", ave);
    printf("\nÊä³ö¿Î³Ì·ÖÊý(¸ß->µÍ):\n");
    output(scores, N);
    
    return 0;
}

void input(int x[], int n) {
    int i;
    
    for(i = 0; i < n; ++i)
        scanf("%d", &x[i]);
}

void output(int x[], int n) {
    int i;
    
    for(i = 0; i < n; ++i)
        printf("%d ", x[i]);
    printf("\n");
}

double average(int x[],int n)
{
    int i,ans=0;
    for(i=0;i<n;++i)
    {
        ans=ans+x[i];
    }
    ans=ans*1.0/n;
    return ans;
}

void bubble_sort(int x[], int n)
{
    int i,j,p;
    for(i=0;i<n;++i)
        for(j = 0;j < n - i - 1;++j)
        {
            if(x[j] < x[j + 1]) {
                p = x[j];
                x[j] = x[j + 1];
                x[j + 1] = p;
        }
}
}

实验任务6

#include <stdio.h>
#include <string.h>
#define N 5
#define M 20
void output(char str[][M], int n);
void bubble_sort(char str[][M], int n);

int main() {
    char name[][M] = {"Bob", "Bill", "Joseph", "Taylor", "George"};
    int i;
    
    printf("输出初始名单:\n");
    output(name, N);
    
    printf("\n排序中...\n");
    bubble_sort(name, N); 
    
    printf("\n按字典序输出名单:\n");
    output(name, N);
    
    return 0;
}

void output(char str[][M], int n) {
    int i;
    
    for(i = 0; i < n; ++i)
        printf("%s\n", str[i]);
}

void bubble_sort(char str[][M], int n)
{
    int i,j;
    char c[M];
    for(i=0;i<n;++i)
        for(j=0;j<i-j-1;j++)
        {
            if(strcmp(str[i],str[i+1])>0)
            {
                strcpy(c, str[j]);
                strcpy(str[j], str[j+1]);
                strcpy(str[j+1], c);
            }
        }
}

实验任务7

#include<stdio.h>
#include<string.h>
#define N 1000
int main()
{
    int length,i,j,m=0;
    char x[N];
    scanf("%s",x);
    length = strlen(x);
    for(i=0;i<length;++i)
    {
        for(j=0;j<i;j++)
        {
            if(x[j]==x[i])
            m=1;
        }
    }
    if(m==1)
    printf("YES\n");
    else
    printf("NO\n");
    
    return 0;
 } 

实验任务8

 

#include <stdio.h>
#define N 100
#define M 4
void output(int x[][N], int n); // 函数声明
void rotate_to_right(int x[][N], int n); // 函数声明
int main() 
{
      int t[][N] = {{21, 12, 13, 24},{25, 16, 47, 38},{29, 11, 32,},{42, 21, 33, 10}};
   printf("原始矩阵:\n");
    output(t, M); // 函数调用数调用
    printf("变换后矩阵:\n");
    rotate_to_right(t, M); // 函
    output(t, M); // 函数调用
    return 0;
}
// 函数定义
// 功能: 输出一个n*n的矩阵x
void output(int x[][N], int n) {
    int i, j;
    for (i = 0; i < n; ++i)
    {
        for (j = 0; j < n; ++j)
            printf("%4d", x[i][j]);
    printf("\n");
}

}
void rotate_to_right(int x[][N], int n)
{
    int i,j,b[M];
    for(i=0;i<M;i++)
        {
            b[i]=x[i][M-1];
        }
        for(i=0;i<n;i++)
            {
            for(j=M-1;j>0;--j)
                {
                    x[i][j]=x[i][j-1];
                    
                }
            x[i][0]=b[i];
            }
}
}