java 判断IP是否符合限定的IP范围内 

 1 /* 判断是否是内网IP */
 2     public static boolean isInnerIP(String ipAddress) {
 3         boolean isInnerIp = false;
 4         long ipNum = getIpNum(ipAddress);
 5         /**
 6          * 私有IP：A类 10.0.0.0-10.255.255.255 B类 172.16.0.0-172.31.255.255 C类
 7          * 192.168.0.0-192.168.255.255 当然，还有127这个网段是环回地址
 8          **/
 9         long aBegin = getIpNum("10.0.0.0");
10         long aEnd = getIpNum("10.255.255.255");
11         long bBegin = getIpNum("172.16.0.0");
12         long bEnd = getIpNum("172.31.255.255");
13         long cBegin = getIpNum("192.168.0.0");
14         long cEnd = getIpNum("192.168.255.255");
15         isInnerIp = isInner(ipNum, aBegin, aEnd)
16                 || isInner(ipNum, bBegin, bEnd) || isInner(ipNum, cBegin, cEnd)
17                 || ipAddress.equals("127.0.0.1");
18         return isInnerIp;
19     }
20 
21     /* 获取IP数 */
22     private static long getIpNum(String ipAddress) {
23         String[] ip = ipAddress.split("\\.");
24         long a = Integer.parseInt(ip[0]);
25         long b = Integer.parseInt(ip[1]);
26         long c = Integer.parseInt(ip[2]);
27         long d = Integer.parseInt(ip[3]);
28         long ipNum = a * 256 * 256 * 256 + b * 256 * 256 + c * 256 + d;
29         return ipNum;
30     }
31 
32     private static boolean isInner(long userIp, long begin, long end) {
33         return (userIp >= begin) && (userIp <= end);
34     }
 1     public static void main(String[] args) {  
 2         String begin = "222.177.202.0";
 3         String end = "222.177.202.255";
 4         String userIP = "222.177.202.11";//客户端IP
 5         long a = getIpNum(begin);
 6         long b = getIpNum(end);
 7         long c = getIpNum(userIP);
 8         if(isInner(Long.valueOf(c),Long.valueOf(a),Long.valueOf(b))){
 9             System.out.println("在范围内");
10         }else{
11             System.out.println("在范围外");
12         }
13     }

 

posted @ 2013-01-17 16:58  suolmz  阅读(3031)  评论(0)    收藏  举报