JSP第一次课作业

1.求1-100之间素数

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
    <base href="<%=basePath%>">
    
    <title>My JSP 'index.jsp' starting page</title>
	<meta http-equiv="pragma" content="no-cache">
	<meta http-equiv="cache-control" content="no-cache">
	<meta http-equiv="expires" content="0">    
	<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
	<meta http-equiv="description" content="This is my page">
	<!--
	<link rel="stylesheet" type="text/css" href="styles.css">
	-->
  </head>
  
  <body>
  </body>
  
  <%
  	int j,i,sum = 0;
  	for(i=1;i<=100;i++){
  		for(j=2;j<i;j++){
  			if(i % j == 0){
  				break;
  			}
  		}
  		if(j == i){
  			sum += i;
  		}
  	}
   %>
  1-100之间素数和为:
  <%=sum%>
</html>

  

2.求1-100偶数和

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
    <base href="<%=basePath%>">
    
    <title>My JSP 'index.jsp' starting page</title>
	<meta http-equiv="pragma" content="no-cache">
	<meta http-equiv="cache-control" content="no-cache">
	<meta http-equiv="expires" content="0">    
	<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
	<meta http-equiv="description" content="This is my page">
	<!--
	<link rel="stylesheet" type="text/css" href="styles.css">
	-->
  </head>
  
  <body>
  </body>
  
  <%
  	int i,sum = 0;
  	for( i=1;i<=100;i++){
  		if(i % 2 == 0){
  			sum += i;
  		}
  	}
   %>
  1-100之间偶数和为:
  <%=sum%>
</html>

  

posted @ 2021-03-03 15:39  Noufff  阅读(82)  评论(0)    收藏  举报