实验六
实验任务4
实验代码：
#include <stdio.h>
#define N 10
typedef struct{
char isbn[20];
char name[80];
char author[80];
double sales_price;
int sales_count;
}book;
void output(book x[],int n);
void sort(book x[],int n);
double sales_amount(book x[],int n);
int main(){
book x[N]={
{"978-7-5327-6082-4","门将之死","罗纳德.伦",42,51},
{"978-7-308-17047-5","自由与爱之地：入以色列记","云也退",49,30},
{"978-7-5404-9344-8","伦敦人","克莱格泰勒",68,27},
{"978-7-5447-5246-6","软件体的生命周期","特德姜",35,90},
{"978-7-5722-5475-8","芯片简史","汪波",74.9,49},
{"978-7-5133-5750-0","主机战争","布莱克.J.哈里斯",128,42},
{"978-7-2011-4617-1","世界尽头的咖啡馆","约翰·史崔勒基",22.5,44},
{"978-7-5133-5109-6","你好外星人","英国未来出版集团",118,42},
{"978-7-1155-0509-5","无穷的开始：世界进步的本源","戴维·多伊奇",37.5,55},
{"978-7-229-14156-1","源泉","安.兰德",84,59}
};
printf("图书销量排名（按销售册数）：\n");
sort(x,N);
output(x,N);
printf("\n图书销售总额：%.2f\n",sales_amount(x,N));
return 0;
}
void output(book x[],int n){
int i;
printf("ISBN号\t\t\t书名\t\t\t 作者\t\t\t售价\t销售册数\n");
for(i=0;i<n;++i)
printf("%-20s%-30s%-20s%.1f\t%d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count);
}
void sort(book x[],int n){
int i,j;
book t;
for(i=0;i<n;++i){
for(j=0;j<n-i;++j){
if(x[j].sales_count<x[j+1].sales_count){
t=x[j+1];
x[j+1]=x[j];
x[j]=t;
}
}
}
}
double sales_amount(book x[],int n){
int i;
double sum=0;
for(i=0;i<n;++i){
sum+=x[i].sales_count*x[i].sales_price;
}
return sum;
}
运行截图：
实验任务5
实验代码：
#include<stdio.h>
typedef struct{
int year;
int month;
int day;
}Date;
void input(Date *pd);
int day_of_year(Date d);
int compare_dates(Date d1,Date d2);
void test1(){
Date d;
int i;
printf("输入日期：（以形如2025-06-01这样的形式输入）\n");
for(i=0;i<3;++i){
input(&d);
printf("%d-%02d-%02d是这一年中第%d天\n\n",d.year,d.month,d.day,day_of_year(d));
}
}
void test2(){
Date Alice_birth,Bob_birth;
int i;
int ans;
printf("输入Alice和Bob出生日期：（以形如2025-06-01这样的形式输入）\n");
for(i=0;i<3;++i){
input(&Alice_birth);
input(&Bob_birth);
ans=compare_dates(Alice_birth,Bob_birth);
if(ans==0)
printf("Alice和Bob一样大\n\n");
else if(ans==-1)
printf("Alice比Bob大\n\n");
else
printf("Alice比Bob小\n\n");
}
}
int main(){
printf("测试1：输入日期，打印输出这是一年中第多少天\n");
test1();
printf("\n测试2：两个人年龄大小关系\n");
test2();
}
void input(Date *pd){
scanf("%d-%d-%d",&(pd->year),&(pd->month),&(pd->day));
}
int day_of_year(Date d){
int a,dan=0,shuang=0;
if((d.year%4==0&&d.year%100!=0)||d.year%400==0){
if(d.month==1)
a=d.day;
else if(d.month==2)
a=31+d.day;
else{
if(d.month%2==0){
dan=d.month/2;
shuang=d.month/2-2;
a=31*dan+30*shuang+29+d.day;}
else{
dan=d.month/2;
shuang=d.month/2-1;
a=31*dan+30*shuang+29+d.day;
}
}
}
else{
if(d.month==1)
a=d.day;
else if(d.month==2)
a=31+d.day;
else{
if(d.month%2==0){
dan=d.month/2;
shuang=d.month/2-2;
a=31*dan+30*shuang+28+d.day;}
else{
dan=d.month/2;
shuang=d.month/2-1;
a=31*dan+30*shuang+28+d.day;
}
}return a;
}
}
int compare_dates(Date d1,Date d2){
int i,a1,a2;
a1=day_of_year(d1);
a2=day_of_year(d2);
if(d1.year==d2.year){
if(a1<a2)
i=-1;
else if(a1>a2)
i=1;
else
i=0;}
else{
if(d1.year<d2.year)
i=-1;
else
i=1;
}
return i;
}
运行截图：
实验任务6
实验代码：
#include<stdio.h>
#include<string.h>
enum role{admin,student,teacher};
typedef struct{
char username[20];
char password[20];
enum role type;
}account;
void output(account x[],int n);
int main(){
account x[]={
{"A1001","123456",student},
{"A1002","123abcdef",student},
{"A1009","Xyz12121",student},
{"X1009","9213071x",admin},
{"c11553","129dfg32k",teacher},
{"X3005","921kfmg917",student}};
int n;
n=sizeof(x)/sizeof(account);
output(x,n);
return 0;
}
void output(account x[],int n){
int i,j;
for(i=0;i<n;++i){
printf("%-20s",x[i].username);
for(j=0;j<strlen(x[i].password);++j)
printf("*");
printf("\t\t\t");
switch(x[i].type){
case (admin):printf("admin\n");break;
case (student):printf("student\n");break;
case (teacher):printf("teacher\n");break;
default:break;
}
}
}
运行截图：
实验任务7
实验代码：
#include<stdio.h>
#include<string.h>
typedef struct{
char name[20];
char phone[12];
int vip;
}contact;
void set_vip_contact(contact x[],int n,char name[]);
void output(contact x[],int n);
void display(contact x[],int n);
#define N 10
int main(){
contact list[N]={
{"刘一", "15510846604", 0},
{"陈二", "18038747351", 0},
{"张三", "18853253914", 0},
{"李四", "13230584477", 0},
{"王五", "15547571923", 0},
{"赵六", "18856659351", 0},
{"周七", "17705843215", 0},
{"孙八", "15552933732", 0},
{"吴九", "18077702405", 0},
{"郑十", "18820725036", 0}};
int vip_cnt,i;
char name[20];
printf("显示原始通讯录信息：\n");
output(list,N) ;
printf("输入要设置的紧急联系人个数：");
scanf("%d",&vip_cnt);
printf("输入%d个紧急联系人姓名：\n",vip_cnt);
for(i=0;i<vip_cnt;++i){
scanf("%s",name);
set_vip_contact(list,N,name);
}
printf("\n显示通讯录列表：（按姓名字典序升序排列，紧急联系人最先显示）\n");
display(list,N);
return 0;
}
void set_vip_contact(contact x[],int n,char name[]){
int i,j;
for(i=0;i<n;++i){
if(strcmp(x[i].name,name)==0)
x[i].vip=1;
}
}
void display(contact x[],int n){
int i,j;
contact t;
for(i=0;i<n-1;++i){
for(j=0;j<n-1-i;++j){
if(x[j].vip<x[j+1].vip){
t=x[j];
x[j]=x[j+1];
x[j+1]=t;
}
if(x[j].vip==0)
if(strcmp(x[j].name,x[j+1].name)>0){
t=x[j];
x[j]=x[j+1];
x[j+1]=t;
}
}
}
for(i=0;i<n;++i){
printf("%-10s%-15s",x[i].name,x[i].phone);
if(x[i].vip)
printf("%5s","*");
printf("\n");
}
}
void output(contact x[],int n){
int i;
for(i=0;i<n;++i){
printf("%-10s%-15s",x[i].name,x[i].phone);
if(x[i].vip)
printf("%5s","*");
printf("\n");
}
}
运行截图：
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